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Ainat [17]
3 years ago
9

On one highway, Gabriela noticed that they passed mile marker 123 at 1:00. She then saw that they reached mile marker 277at 3:00

. Since Mr. Morales was driving at a constant speed, their mile-marker location over time can be represented by a line where the time in hours is the independent variable and the mile marker is the dependent variable. The points (1,123) and (3,277) are two points on this line.
What is the value of the slope of this line?
Mathematics
1 answer:
Elena L [17]3 years ago
6 0

<u>Given</u>:

Let time be the independent variable.

Let mile marker be the dependent variable.

On one highway, Gabriela noticed that they passed mile marker 123 at 1:00. She then saw that they reached mile marker 277 at 3:00 and Mr. Morales was driving at a constant speed.

The coordinates of the points on this line are (1,123) and (3,277)

We need to determine the slope of the line.

<u>Slope of the line:</u>

The slope of the line can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Substituting the points (1,123) and (3,277) in the above formula, we get;

m=\frac{277-123}{3-2}

m=\frac{154}{1}

m=154

Therefore, the value of the slope of this line is 154.

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F(x + h) – f(x)
olga nikolaevna [1]

9514 1404 393

Answer:

  -6x² -6xh -2h²

Step-by-step explanation:

Apparently, you want ...

  (f(x+h) -f(x))/h

for f(x) = 14 -2x³

That difference quotient is ...

  \dfrac{f(x+h)-f(x)}{h}=\dfrac{(14 -2(x+h)^3)-(14-2x^3)}{h}\\\\ =\dfrac{14-2(x^2 +3x^2h+3xh^2+h^3)-14+2x^3}{h}=\dfrac{-6x^2h-6xh^2-2h^3}{h}\\\\ =\boxed{-6x^2 -6xh-2h^2}

3 0
3 years ago
Sacramento County high school seniors have an average SAT score of 1,020. From a random sample of 144 Sacramento High School stu
kari74 [83]

Answer:

We need to conduct a hypothesis in order to check if the high school students are representative of the overall population (or if the true mean is 1020 or not), the system of hypothesis would be:    

Null hypothesis:\mu = 1020    

Alternative hypothesis:\mu \neq 1020  

Step-by-step explanation:

Previous concepts  and data given  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

\bar X=1100 represent the sample mean    

s=144 represent the sample standard deviation  

n=144 represent the sample selected  

\alpha significance level    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the high school students are representative of the overall population (or if the true mean is 1020 or not), the system of hypothesis would be:    

Null hypothesis:\mu = 1020    

Alternative hypothesis:\mu \neq 1020    

If we analyze the size for the sample is > 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic  

We can replace in formula (1) the info given like this:    

t=\frac{1100-1020}{\frac{144}{\sqrt{144}}}=6.67      

P-value  

First we need to calculate the degrees of freedom given by:

df=n-1=144-1 =143

Then since is a two sided test the p value would be:    

p_v =2*P(t_{144}>6.67)=2.59x10^{-10}    

Conclusion    

If we compare the p value and a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the population mean is significant different from 1020 at 5% of significance.    

6 0
3 years ago
How to put the sum 7/10 in
alexdok [17]
That is a fraction, if you want to put it into decimal form, it would be equivalent to 0.7
8 0
4 years ago
It is possible to score higher than 1600 on the combined mathematics and reading portions of the SAT, but scores 1600 and above
Citrus2011 [14]

Answer:

The proportion of scores reported as 1600 is 0.0032

Step-by-step explanation:

Let X be the score for 1 random person in SAT combining maths and reading. X has distribution approximately N(μ = 1011,σ = 216).

In order to make computations, we standarize X to obtain a random variable W with distribution approximately N(0,1)

W = \frac{X-\mu}{\sigma} = \frac{X-1011}{216} \simeq N(0,1)

The values of the cummulative distribution function of the standard Normal random variable, lets denote it \phi are tabulated, you can find those values in the attached file. Now, we are ready to compute the probability of X being bigger than 1600

P(1600< X) = P(\frac{1600-1011}{216} < \frac{X-1011}{216}) = P(2.7269 < W) = 1- \phi(2.7269)\\= 1- 0.9968 = 0.0032

Hence, the proportion of scores reported as 1600 is 0.0032.

Download pdf
5 0
4 years ago
Solve 10/y = 5/2 the solution is y=
pantera1 [17]
Y should equal 4 because if you have 10/4 then divide the fraction by 2 then it gives you 5/2
3 0
4 years ago
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