Think about this as a table of values where domain is the x values and range is the y values.
f(4) wants the y-value when the x-value is 4
f(4) = 1/2
The second question wants us to find the x-value when f(x) also known as the y-value is 4.
f(x) = 4
x = 8
answers: 1/2, 8
Answer:
The vertex of a quadratic equation corresponds to the point where the maximum or minimum value is located.
If the function has a positive leading coefficient, the vertex corresponds to the minimum value.
If it has a negative leading coefficient, the vertex corresponds to the maximum valuevalue
If the vertex is located at
(–2, 0)
The possibilities are
y = (x-2)^2
or,
y = - (x-2)^2
Since the problem tells us the answer, we adopt the positive values
Answer:
y = (x-2)^2
See attached picture
Answer:
240 m³
Step-by-step explanation:
volume = length × width × depth
240 m³ = 20 m × 1 m × 12 m
<h2>y = -0.25x + 2</h2><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
Answer:
5.
Step-by-step explanation:
9y - 6 + 51 = 90
9y + 45 = 90
9y = 45
y = 5.