Answer:
The fraction is 1/4
Step-by-step explanation:
we know that
The area of an equilateral triangle, using the law of sines is equal to



where
x is the length side of the triangle
In this problem
Let
b ----> the length side of the regular hexagon
2b ---> the length side of the equilateral triangle
step 1
Find the area of the six triangles
Multiply the area of one triangle by 6
![A=6[x^{2}\frac{\sqrt{3}}{4}]](https://tex.z-dn.net/?f=A%3D6%5Bx%5E%7B2%7D%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%5D)

we have

substitute

step 2
Find the area of the regular hexagon
Remember that, a regular hexagon can be divided into 6 equilateral triangles
so
The area of the regular hexagon is the same that the area of 6 equilateral triangles

we have

substitute

step 3
To find out what fraction of the total area of the six triangles is the area of the hexagon, divide the area of the hexagon by the total area of the six triangles

A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

We are tasked to solve for the number of ways the 8 students be competing for the 1st, 2nd, 3rd, 4th voilin chair in the schools orchestra. The number of ways if can only be filled is though the formula used in number counting, that is
8x7x6x5
Therefore, there are 1680 ways
Answer:
6x²5y²6 cm²
Step-by-step explanation:
(2xy3) x (4x5y6)
(2x) x (4x) = 6x²
(y) x (5y) =5y²
6x²5y²6 cm²
6z to the 4th power - 2z to the 3rd power