The slope of the line which passes through (19,-16) and (-7,-15) is -1/26.
Given that the points through which the line passes is (19,-16) and (-7,-15).
We are required to find the slope of the line which passes through (19,-16) and (-7,-15).
The slope of a line is basically a measure of its steepness.It is basically the difference between y coordinate divided by the difference between x coordinate. We can form an equation with the help of the slope.
Points=(19,-16) and (-7,-15)
Slope=(-15+16)/(-7-19)
=1/-26
=-1/26
Hence the slope of the line which passes through (19,-16) and (-7,-15) is -1/26.
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It would be 0.75 as a decimal or 3/4
152.4cm. 2.54cm = 1in. 60in x (2.54cm/1in) = 152.4cm.
Step-by-step explanation:
4x2+8x−3=0
For this equation: a=4, b=8, c=-3
4x2+8x+−3=0
Step 1: Use quadratic formula with a=4, b=8, c=-3.
x=
−b±√b2−4ac
2a
x= −(8)±√(8)2−4(4)(−3)
2(4)
x= −8±√112
8 x=−1+
1 2 √7 or x=−1+
−1 2 √7
Answer: x=−1+
1 2√7 or x=−1+
−1 2 √7
Answer:
c=10
Step-by-step explanation:
pythagreom theroem
c (hypotenuse) = 
plug in values for a and b
c=
c=
c=
c=10
