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3 years ago

15

Adrian can purchase a 10-pound item from several different sellers. Which is the best buy?

1 answer:

iogann1982 [59]3 years ago

6 0

The answer is C. If he buys A, he gets $50 price, plus $10 worth of per pound shipping, so it is $60. For B, he pays $20 per pound worth of shipping, already with a $47 price, so it’s $67. By buying it at the store with the $5 coupon, he only pays $55.

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Select the correct answer. (Remember there will be a length, width and height and they are all different numbers).

Bogdan [553]

A) 122 in^2, this is because 3 x 7 x 2= 42, 4 x 7 x 2= 56, 3 x 4 x 2= 24, once you add up all the sums it equals 122

3 0

3 years ago

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a pipe is 30 feet long. it needs to be cut into pieces that are 3/5 feet long. how many pieces can be made from the pipe

Rudiy27

It's basically 30 divide by 3/5
which becomes 30*5/3

The answer is 50

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4 years ago

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Retail price= $120 <br> markup percent= 40%<br> what is the original cost

valina [46]

I believe it would be 72

8 0

3 years ago

Find the area of the surface generated by revolving the curve xequals=StartFraction e Superscript y Baseline plus e Superscript

artcher [175]

Solution :

$x=f(y) = \frac{e^y + e^{-y}}{2} , \ \ \ \ \ 0 \leq y \leq \ln 2$

$\frac{dx}{dy} = \frac{e^y + e^{-y}}{2}$

$\left(\frac{dx}{dy}\right)^2 = \frac{e^{2y} - 2 + e^{-2y}}{4}$

$1+\left(\frac{dx}{dy}\right)^2 = 1+\frac{e^{2y} - 2 + e^{-2y}}{4} = \frac{e^{2y} + 2 + e^{-2y}}{4}$

$= \left(\frac{e^y + e^{-y}}{2}\right)^2$

$\sqrt{1+\left(\frac{dx}{dy}\right)^2} = \sqrt{\left(\frac{e^y + e^{-y}}{2}\right)^2}=\frac{e^y + e^{-y}}{2}$

$S = \int_{y=a}^b 2 \pix \sqrt{1+\left(\frac{dx}{dy}\right)^2 } \ dy$

$=\int_{0}^{\ln2} 2 \pi \left(\frac{e^y+e^{-y}}{2}\right) \left(\frac{e^y+e^{-y}}{2}\right) \ dy$

$=\frac{\pi}{2}\int_{0}^{\ln 2}(e^y+e^{-y})^2 \ dy = \frac{\pi}{2}\int_{0}^{\ln 2}(e^{2y}+e^{-2y}+2) \ dy$

$=\frac{\pi}{2} \left[ \frac{e^{2y}}{2} + \frac{e^{-2y}}{-2} + 2y \right]_2^{\ln 2}$

$=\frac{\pi}{2} \left[ \left(\frac{e^{2 \ln 2}}{2} + \frac{e^{-2\ln2}}{-2} + 2 \ln2 \right) - \left( \frac{e^0}{2} + \frac{e^0}{-2}+0\right) \right]$

$=\frac{\pi}{2}\left[ \frac{e^{\ln4}}{2} - \frac{e^{\ln(1/4)}}{2} + \ln 4 - \left( \frac{1}{2} - \frac{1}{2} + 0 \right) \right]$

$=\frac{\pi}{2} \left[\frac{4}{2} -\frac{1/4}{2} + \ln 4 \right]$

$=\frac{\pi}{2} \left[ 2-\frac{1}{8} + \ln 4 \right]$

$=\left( \frac{15}{8} + \ln 4 \right) \frac{\pi}{2}$

Therefore, $S = \frac{15}{16} \pi + \pi \ln 2$

3 0

3 years ago

A three-dimensional shape , such as a ball , whose surface consists of all the point that are a given distance from the center o

docker41 [41]

That's a sphere. Look up "sphere" for more info.

3 0

4 years ago

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