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3 years ago

Patricia buys a round dinner table the radius of the dinner table is 6 m what is the area of the table table

Mathematics

2 answers:

PtichkaEL [24]3 years ago

8 0

Answer:

18.8495559215 m

Step-by-step explanation:

It is 6 times pi.

GREYUIT [131]3 years ago

4 0

Answer:

113.04

Step-by-step explanation:

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Mr. Smith wants to order some pizza and cheese pizza cost $11 and pepperoni pizza cost $12.50 if you bought 13 pieces total and

Triss [41]

Answer: Mr Smith bought 7 pepperoni pizza

Step-by-step explanation:

Step 1

cost of cheese pizza =$11

pepperoni pizza cost =$12.50

let number cheese pizza be represented as c

and number of pepperoni pizza be represented as p

such that the total number of pizza bought which equals 13 can be represented as

c+ p= 13

and total cost of both pizza can be expressed as

11c+ 12.50p =153.50

Step 2 Solving

c+ p= 13

11c+ 12.50p =153.50

By elimination method, Multiply equation 1 by 11 and subtract the new equation from equation 2

11c+ 12.50p =153.50

11c+ 11p=143.

1.5p =10.5

p= 10.5/ 1.5 =7

c+ p= 13

c= 13-p =13-7=6

Therefore Mr Smith bought 6 cheese pizza and 7 pepperoni pizza

6 0

3 years ago

Mr. Kershner is a school nurse. He uses, on average, 24 self-adhesive bandages during each spring month: March, April, and May.

Furkat [3]

Answer:

168

Step-by-step explanation:

24 times 3 is 72 then also 24 times 4 is 96 add that and get 168

6 0

3 years ago

Read 2 more answers

What is 1,000,000 in words?

Zielflug [23.3K]

1,000,000 = one million

Good Luck! :)

4 0

3 years ago

Taylor earned $48 for 6 hours of babysitting and $68 for 8.5 hours of babysitting. How long would she have to babysit to earn $3

ZanzabumX [31]

48÷6=$8 per hour
So
32÷8=4 hours

6 0

3 years ago

A ball of radius 15 has a round hole of radius 5 drilled through its center. Find the volume of the resulting solid. Hint: The u

OverLord2011 [107]

Answer:

The volume of the ball with the drilled hole is:

$\displaystyle\frac{8000\pi\sqrt{2}}{3}$

Step-by-step explanation:

See attached a sketch of the region that is revolved about the y-axis to produce the upper half of the ball. Notice the function y is the equation of a circle centered at the origin with radius 15:

$x^2+y^2=15^2\to y=\sqrt{225-x^2}$

Then we set the integral for the volume by using shell method:

$\displaystyle\int_5^{15}2\pi x\sqrt{225-x^2}dx$

That can be solved by substitution:

$u=225-x^2\to du=-2xdx$

The limits of integration also change:

For x=5: $u=225-5^2=200$

For x=15: $u=225-15^2=0$

So the integral becomes:

$\displaystyle -\int_{200}^{0}\pi \sqrt{u}du$

If we flip the limits we also get rid of the minus in front, and writing the root as an exponent we get:

$\displaystyle \int_{0}^{200}\pi u^{1/2}du$

Then applying the basic rule we get:

$\displaystyle\frac{2\pi}{3}u^{3/2}\Bigg|_0^{200}=\frac{2\pi(200\sqrt{200})}{3}=\frac{400\pi(10)\sqrt{2}}{3}=\frac{4000\pi\sqrt{2}}{3}$

Since that is just half of the solid, we multiply by 2 to get the complete volume:

$\displaystyle\frac{2\cdot4000\pi\sqrt{2}}{3}$

$=\displaystyle\frac{8000\pi\sqrt{2}}{3}$

5 0

3 years ago