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andreev551 [17]
2 years ago
12

Patricia buys a round dinner table the radius of the dinner table is 6 m what is the area of the table table

Mathematics
2 answers:
PtichkaEL [24]2 years ago
8 0

Answer:

18.8495559215 m

Step-by-step explanation:

It is 6 times pi.

GREYUIT [131]2 years ago
4 0

Answer:

113.04

Step-by-step explanation:

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Kylie explained that will result in a difference of squares because . Which statement best describes Kylie’s explanation?
satela [25.4K]

Answer: that not a real question it cant be answered has to be missing something

Step-by-step explanation:)

8 0
2 years ago
Please help, I didn't learn this in class!
NemiM [27]
Solve the following system using elimination:
{-2 x + 2 y + 3 z = 0 | (equation 1)
{-2 x - y + z = -3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x - 3 y - 2 z = -3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+3 y + 2 z = 3 | (equation 2)
{2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+3 y + 2 z = 3 | (equation 2)
{0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y + 6 z = 5 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+5 y+0 z = 5 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)


Divide equation 2 by 5:
{-(2 x) + 2 y + 3 z = 0 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:
{-(2 x) + 0 y+3 z = -2 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
v0 x+0 y+z = 0 | (equation 3)


Subtract 3 × (equation 3) from equation 1:
{-(2 x)+0 y+0 z = -2 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:
{x+0 y+0 z = 1 | (equation 1)
{0 x+y+0 z = 1 | (equation 2)
{0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1, y = 1, z = 0

7 0
3 years ago
• What is the solution to 5x+ 20 = 7(x+2)?
o-na [289]

For this case we must find the solution of the following equation:

5x + 20 = 7 (x + 2)

Applying distributive property on the right side of the equation we have:

5x + 20 = 7x + 14

Subtracting 7x from both sides of the equation:

5x-7x + 20 = 14\\-2x + 20 = 14

Subtracting 20 from both sides of the equation:

-2x = 14-20

Different signs are subtracted and the major sign is placed.

-2x = -6

Dividing between -2 on both sides of the equation:

x = \frac {-6} {- 2}\\x = 3

Thus, the solution of the equation isx = 3

Answer:

x = 3

6 0
3 years ago
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kakasveta [241]

i can't really see the image but i'm sure it's pretty cool (:

8 0
3 years ago
What is the strongest relationship you can infer between two variables from this statement?
Dmitry [639]

Answer:

hope this helps you with your question

3 0
3 years ago
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