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2 years ago

Explain why you would make one of the addends a tens number when solving an addition problem.

Mathematics

1 answer:

____ [38]2 years ago

6 0

I see so many people ask this. What does this mean?

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HELLLPPPPPPP FASTTTTTTTT Jeremiah has to pay for his phone calls that are $.11 the minute if he has eight dollars how many minut

fenix001 [56]

72 minutes or an hour and 12 minutes

3 0

3 years ago

Read 2 more answers

Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon

Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

$h(t)=-16t^2+40t+5$

we know that

When the ball hits the ground, the height is equal to zero

$-16t^2+40t+5=0$

The formula to solve a quadratic equation of the form

$at^{2} +bt+c=0$

is equal to

$t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+40t+5=0$

$a=-16\\b=40\\c=5$

substitute in the formula

$t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}$

$t=\frac{-40\pm\sqrt{1,920}} {-32}$

$t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec$

$t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec$

therefore

The solution is t=2.62 seconds

4 0

2 years ago

Can you help me with this one

Vilka [71]

The answer is B. (Elite members earn 3 more points for every dollar spent and are awarded 100 more points per month than a regular memeber).

3 0

3 years ago

A three inch diameter pulley on an electric motor that runs at 1800

Bezzdna [24]

Answer:

a) 3 inch pulley: 11,309.7 radians/min

6) 6 inch pulley: 5654.7 radians/min

b) 900 RPM (revolutions per minute)

Step-by-step explanation:

Hi!

When a pulley wirh radius R rotantes an angle θ, the arc length travelled by a point on its rim is Rθ. Then the tangential speed V is related to angular speed ω as:

$V=R\omega$

When you connect two pulleys with a belt, if the belt doesn't slip, each point of the belt has the same speed as each point in the rim of both pulleys: Then, both pulleys have the same tangential speed:

$\omega_1 R_1 = \omega_2 R_2\\$