Answer:
The values of x for which the model is 0 ≤ x ≤ 3
Step-by-step explanation:
The given function for the volume of the shipping box is given as follows;
V = 2·x³ - 19·x² + 39·x
The function will make sense when V ≥ 0, which is given as follows
When V = 0, x = 0
Which gives;
0 = 2·x³ - 19·x² + 39·x
0 = 2·x² - 19·x + 39
0 = x² - 9.5·x + 19.5
From an hint obtained by plotting the function, we have;
0 = (x - 3)·(x - 6.5)
We check for the local maximum as follows;
dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0
6·x² - 38·x + 39 = 0
x² - 19/3·x + 6.5 = 0
x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2
∴ x = 1.288, or 5.045
At x = 1.288, we have;
V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99
V ≈ 22.99 in.³
When x = 5.045, we have;
V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023
Therefore;
V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5
The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.
Answer:
x= 2.73cm
<u>1cm : 0.6828 = 4cm : 2.73cm</u>
For the same angle we just work out 1cm first.
a^2+ b^2= c^2
0.82^2 + b^2 = 1^2 = changing to units 10
6.724 + b^2 = 10
10-6.724 = 2.276
Then x 3 and change units down by 10= 0.6828
Step-by-step explanation:
Below shows why we must convert to mm from cm
a^2+ b^2= c^2
0.82^2 + b^2 = 1^2 =
0.6724 + b^2 = 1
1 - 0.6724 = b = 0.2276
0.2276 x 3 = 0.6828 cm
Answer:
1= 2,400 feet
2= 154 meters
3= 120 pints
4= 2. 056 centigrams
5= 16.1 C
6= 50F
7= -2.8C
1= multiply the length value by 3
2= divide the length value by 10
3= multiply the volume value by 8
4= divide the mass value by 10
5= Take the °F temperature and subtract 32. Multiply this number by 5. Divide this number by 9 to obtain your answer in °C.
6= multiply the temperature in degrees Celsius by 2, and then add 30 to get the (estimated) temperature in degrees Fahrenheit.
Answer:
8 lbs 5 oz
Step-by-step explanation:
When you add 3 lbs, 2 lbs, and 2 lbs you get 7 lbs.
There are 16 oz in a lb. When you add the number of oz you get 21 oz which is the same as 1 lb and 5 oz.
you then add 7 lbs to 1 lb and 5 oz and get 8 lbs and 5 oz.
