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zepelin [54]
3 years ago
5

How does the law of conservation of matter apply to chemical equations? A. The sum of the coefficients on each side of the equat

ion must be the same. B. The sum of the atomic masses on both sides of the equation must be the same. C. The sum of the atomic numbers on both sides of the equation must be the same. D. The total number of atoms of each element on both sides of the equation must be the same.
Physics
2 answers:
irinina [24]3 years ago
5 0
The answer is letter D.
WINSTONCH [101]3 years ago
3 0
D. The total number of atoms of each element on both sides of the equation must be the same
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Answer:

Increase

Explanation:

Resonance is a phenomenon which occurs when a body A in motion set another body B into motion of it own natural frequency. So for resonance to be minimize in a body is to increase the width to span ratio. So as to reduce the overall vibration which affects directly building resonance, the stiffness or trusses and girders should be increase. The increase in this aspect helps to reinforce building structure and support.

3 0
3 years ago
Trong thí nghiệm Y-âng về giao thoa ánh sáng : khoảng cách giữa hai khe là 0,5 mm ; khoảng cách từ mặt phẳng chứa hai khe đến mà
Natalija [7]

không có câu hỏi, trả lời như nào nhỉ?

8 0
3 years ago
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A telephone line has a signal-to-noise ratio of 1000 and a bandwidth of 4 KHz. What is the maximum data rate supported by this l
ivolga24 [154]

Answer:

The maximum data rate supported by this line is 39900 bps

Explanation:

The maximum data rate supported by this line can be obtained using the formula below

c = W*log2(S/N+1)

where;

c is the maximum data rate supported by the line

W is the bandwidth = 4kHz

S/N+1 is the signal to noise ratio = 1001

c = 4*log2(1001)

c = 39868.9 ≅ 39900 bps

Therefore, the maximum data rate supported by this line is 39900 bps

5 0
4 years ago
Why does food coloring diffuse faster in cold water than warm
labwork [276]
Warm water<span> has more energy </span><span>than cold water</span>
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3 years ago
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Two forces F1 and F2 of equal magnitude are applied to a brick of mass 20kg lying on the floor as shown in the figure above. If
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Let F_{1}=F_{2}=F.

Normal force equals (using Newton's third law) N=mg+F\sin30^{o}-F\sin37^{o}.

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7 0
3 years ago
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