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White raven [17]
3 years ago
12

Difference between cold and warm blooded animal.

Physics
1 answer:
Anna [14]3 years ago
6 0

Answer:

Cold blooded animals are those animals that cannot regulate their body temperature and their temperature keeps changing according to their environment. ... Warm blooded animals are the animals that have a constant body temperature and can easily adapt to extreme temperatures as they can regulate their body temperature.

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Which statement is true? CTP hydrolysis can be a source of chemical energy. dATP is the most common source of chemical energy in
Gemiola [76]

1. Statement A is true.

When GTP is hydrolysed, the free energy of hydrolyses is used to power or drive reactions that are favourable energetically.

2. Statement B it true.

ATP is a complex chemical that gives energy for the activities in many living cells. During hydrolyses, chemical energy stored in the energy-rich phosphoanhydride is released. Hence its a common source of chemical energy in cells.

3. Statement C is false.

The hydrolyses of ATP to ADP in the presence of phosphate, releases one mole of ATP which is estimated to be -57Kj/mol not 14Kj/mol. Below is the equation;

ATP + H20 -----> ADP + Pi + Free energy.

4. Statement D is false.

GTP stands for guanosine triphosphate.

ATP stands for adenosine triphosphate

ADP stands for adenosine diphosphate.

3 0
4 years ago
What is the term used for the rate at which distance is traveled?
jeka94
Velocity

Hope this helps
7 0
4 years ago
Read 2 more answers
A solenoid of length 16 cm consists of closely spaced coils of wire wrapped tightly around a wooden core. The magnetic field str
choli [55]

Answer:

B2 = 2.22mT

Explanation:

See attachment for the calculation.

Assuming the angle the magnetic field makes with the direction of current flow is the same in both cases and that the same current flows in both cases, then F1 = F2

See calculation below.

8 0
4 years ago
Critical Thinking 1. One day, a group of neighbourhood degs Started barking on their own. The residents living in that area are
liberstina [14]

The reason behind the barking of the group of neighborhood dogs could be <u>Territorial/Protective</u> or  <u>Alarm/Fear</u>.

What is bark or barking?

Dogs are known for making the most prevalent barking noises. Wolves, coyotes, foxes, seals, and barking owls are a few other creatures that make this sounds. The most typical onomatopoeia for this sound in English, particularly for large dogs, is "woof." The word "bark" can also be used to describe the sound made by numerous canids. A bark is a brief vocalization, as per the researchers at the University of Massachusetts Amherst.

Territorial/Protective: When a person or another animal enters their perceived area, your dog may bark excessively, depending on the breed. The barking frequently gets louder as the threat draws closer. When your dog barks in this manner, he will appear vigilant and sometimes even hostile.

Alarm/Fear: Some dogs will bark in alarm or fear at any sound or item that draws their attention or alarmed them. It's not just in their home country where this can occur. When they are afraid, their tails will be tucked and their ears will be pulled back.

To know more about bark, go to link

brainly.com/question/5082728

#SPJ9

3 0
1 year ago
A diffraction pattern is formed on a screen 130 cm away from a 0.420-mm-wide slit. Monochromatic 546.1-nm light is used. Calcula
notka56 [123]

Answer:

The fractional Intensity \frac{I}{I_{max}} = 0.0146

Given:

wavelength of the light, \lambda = 546.1 nm = 546.1\times 10^{-9} m

slit and screen separation difference, D = 130 cm = 1.3 m

distance of the point from the center of the principal maximum, y = 4.10 mm = 0.041 m

slit width, d = 0.420 mm = 0.420\times 10^{-3}

Solution:

To calculate the fractional intensity, we use the given formula:

\frac{I}{I_{max}} = \frac{sin^{2}\delta }{\frac({\delta}{2})^{2}}             (1)

\delta = \frac{\pi }{\lambda}dsin\theta    

For very small angle:                                        

\delta = \frac{\pi dy}{\lambda D}                                  (2)

where

\delta = total phase angle

\theta = angle of deviation

Using eqn (2):

\delta = \frac{\pi \times 0.42\times 10^{-3}\times 4.1\times 10^{-3} }{546.1\times 10^{-9}\times 1.3} = 7.6202 radians

Now, using eqn (1):

\frac{I}{I_{max}} = \frac{sin^{2}(7.6202) }{(\frac{7.6202}{2})^{2}} = 0.0146

4 0
4 years ago
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