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morpeh [17]
3 years ago
6

A cyclotron operates with a given magnetic field and at a given frequency. If R denotes the radius of the final orbit, the final

particle energy is proportional to:
Physics
1 answer:
Archy [21]3 years ago
5 0

Answer:

the final particle energy is proportional to

Emax \infty\ R^2

Explanation:

The computation of the final particle energy is as follows;

As we know that

Energy is respect with the radious as

Emax = \frac{q^2R^2B^2}{2m}

In the case when other quantities would remains the same or constant

So, the final particle energy is proportional to

Emax \infty\ R^2

The same is to be considered and relevant too

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IrinaK [193]
The size of the forces between you and the planet you're on is
your weight on that planet.

Don't forget that you pull the planet with a force equal to the force
that the planet pulls on you.  Your weight on Earth is the same as
the Earth's weight on you !
6 0
3 years ago
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If you use the same force to push a motorcycle as you would push a bike which one would have more acceleration and why explain u
zaharov [31]

Answer:

The bike would have more acceleration

Explanation:

Accourding to newtons first law a force is equal to its mass multiplied by its acceleration (f=ma) therefore an object with a higher mass compared to an object with a lower mass would experience less acceleration.

Eg.

F=50N

Motorbike M=200kg

F=ma

50=200 x a

50/200=a

0.25m/s/s =a

Bike M=35kg

F=ma

50=35 x a

50/35= a

1.43m/s/s=a

6 0
3 years ago
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Consider a car travelling at 60 km/hr. If the radius of a tire is 25 cm, calculate the angular speed of a point on the outer edg
vlabodo [156]

To solve this problem it is necessary to apply the concepts given in the kinematic equations of movement description.

From the perspective of angular movement, we find the relationship with the tangential movement of velocity through

\omega = \frac{v}{R}

Where,

\omega =Angular velocity

v = Lineal Velocity

R = Radius

At the same time we know that the acceleration is given as the change of speed in a fraction of the time, that is

\alpha = \frac{\omega}{t}

Where

\alpha =Angular acceleration

\omega = Angular velocity

t = Time

Our values are

v = 60\frac{km}{h} (\frac{1h}{3600s})(\frac{1000m}{1km})

v = 16.67m/s

r = 0.25m

t=6s

Replacing at the previous equation we have that the angular velocity is

\omega = \frac{v}{R}

\omega = \frac{ 16.67}{0.25}

\omega = 66.67rad/s

Therefore the angular speed of a point on the outer edge of the tires is 66.67rad/s

At the same time the angular acceleration would be

\alpha = \frac{\omega}{t}

\alpha = \frac{66.67}{6}

\alpha = 11.11rad/s^2

Therefore the angular acceleration of a point on the outer edge of the tires is 11.11rad/s^2

5 0
3 years ago
HELP!! ILL GIVE BRAINLIEST As we've learned so far, the popular model of the solar system shifted over
Mademuasel [1]

Answer:

geotric earth simulator I think ya I have no idea

4 0
3 years ago
It decomposes in a first-order reaction with a rate constant of 14 s–1. how long would it take for an initial concentration of 0
VikaD [51]
The rate constant of a reaction can be computed by the ratio of the changes in the concentration and time take taken for it to decompose. Thus, if the rate constant is given to be 14 M/s, we have 

rate = \frac{-(C_{new} - C_{old})}{t}

where C are the concentration values and t is the time taken for it to decompose.

14 = \frac{-(0.02 - 0.06)}{t}
t = 0.003 s

Thus, it will take 0.003 s for it to decompose.
Answer: 0.003 s

4 0
3 years ago
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