Complete Question
A voltaic cell is constructed with two 
electrodes. The two cell compartment have ![[Zn^{2+}] = 1.6 \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D%20%3D%20%201.6%20%5C%20M)
and ![[Zn^{2+}] = 2.00*10^{-2} \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D%20%3D%20%202.00%2A10%5E%7B-2%7D%20%5C%20%20M)
respectively.
What is the cell emf for the concentrations given? Express your answer using two significant figures
Answer:
The value is 
Explanation:
Generally from the question we are told that
The concentration of ![[Zn^{2+}]](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D)
at the cathode is ![[Zn^{2+}]_a = 1.6 \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D_a%20%3D%20%201.6%20%5C%20M)
The concentration of at the anode is ![[Zn^{2+}]_c = 2.00*10^{-2} \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D_c%20%3D%20%202.00%2A10%5E%7B-2%7D%20%5C%20%20M)
Generally the the cell emf for the concentration is mathematically represented as
![E = E^o - \frac{0.0591}{2} log\frac{[Zn^{2+}]a}{ [Zn^{2+}]c}](https://tex.z-dn.net/?f=E%20%3D%20%20E%5Eo%20-%20%5Cfrac%7B0.0591%7D%7B2%7D%20log%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5Da%7D%7B%20%5BZn%5E%7B2%2B%7D%5Dc%7D)
Generally the 
is the standard emf of a cell, the value is 0 V
So
![E = 0 - \frac{0.0591}{2} * log[\frac{ 2.00*10^{-2}}{1.6} ]](https://tex.z-dn.net/?f=E%20%3D%20%200%20%20-%20%20%5Cfrac%7B0.0591%7D%7B2%7D%20%20%2A%20log%5B%5Cfrac%7B%202.00%2A10%5E%7B-2%7D%7D%7B1.6%7D%20%5D)
=>
osmosis and cellular transport - the physics of molecular movement, kinetic energy and diffusion.
Answer:
4.3 m/s
Explanation:
Using conservation of momentum, assume that the collision is elastic and that the 3.0 g ball stuck with the carton
3.0 g = 3 / 1000 = 0.003 kg = m₁
40 g = 40 / 1000 = 0.04 kg = m₂, u₂ = 0 since the body is stationary and v = 0.3m/s
m₁u₁ + m₂u₂ = v ( m₁ + m₂)
0.003 u₁ = 0.30 ( 0.003 + 0.04) = 0.0129
u₁ = 0.0129 / 0.003 = 4.3 m/s
A hockey puck glides to the right across the ice
Answer:
I believe the answer is C.
Explanation: Hope this helps and have a great day! :)
