The upward normal force exerted by the floor is 710 N on an elevator passenger who weighs 720 N . You may want to review (Pages
1 answer:
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Answer:
I = 4.75 A
Explanation:
To find the current in the wire you use the following relation:
(1)
E: electric field E(t)=0.0004t2−0.0001t+0.0004
ρ: resistivity of the material = 2.75×10−8 ohm-meters
J: current density
The current density is also given by:
(2)
I: current
A: cross area of the wire = π(d/2)^2
d: diameter of the wire = 0.205 cm = 0.00205 m
You replace the equation (2) into the equation (1), and you solve for the current I:
Next, you replace for all variables:
hence, the current in the wire is 4.75A
Answer:
9.96 m/s
Explanation:
mass of car, m = 487 kg
radius of track, R = 53.3 m
coefficient of static friction, μ = 0.19
acceleration due to gravity, g = 9.8 m/s^2
let v be the maximum speed so that the car can go without flying off the track.
The formula for the maximum speed is given by
vmax = 9.96 m/s