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Inga [223]
3 years ago
11

Can someone explain this to me??? Are you able to see the picture?

Mathematics
1 answer:
Butoxors [25]3 years ago
4 0

Answer:

P' = (3, 0)

Step-by-step explanation:

You are translating the point (x, y) of (5, -5) to the left 2 units and up 5 units.   The x value changes when shifting left or right.  So the x value shifts to the left 2 units, meaning it shifts left on the number line, so it reduces by 2 units. The y value changes when shifting up or down.  So the y value shifts up 5 units, so it increases in value by 5 units

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Computer A: A graph has programs on the x-axis and megabytes on the y-axis. A line goes through (0, 32) and (2, 176). Computer B
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Answer:

its C

Step-by-step explanation:

8 0
3 years ago
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Hi can anybody explain to me how to do this I'm kinda confused . 5×[5(-7)]​
telo118 [61]

Answer:

5 × [5(-7)]

= 5 × (-35)   ---- 5 × (-7) = -35

= -175

4 0
3 years ago
The base of an aquarium with given volume V is made of slate and the sides are made of glass. If the slate costs seven times as
Olin [163]

Answer:

x = ∛(2V/7)

y = ∛(2V/7)

z = 3.5 [∛(2V/7)]

{x,y,z} = { ∛(2V/7), ∛(2V/7), 3.5[∛(2V/7)] }

Step-by-step explanation:

The aquarium is a cuboid open at the top.

Let the dimensions of the base of the aquarium be x and y.

The height of the aquarium is then z.

The volume of the aquarium is then

V = xyz

Area of the base of the aquarium = xy

Area of the other faces = 2xz + 2yz

The problem is to now minimize the value of the cost function.

The cost of the area of the base per area is seven times the cost of any other face per area.

With the right assumption that the cost of the other faces per area is 1 currency units, then, the cost of the base of the aquarium per area would then be 7 currency units.

Cost of the base of the aquarium = 7xy

cost of the other faces = 2xz + 2yz

Total cost function = 7xy + 2xz + 2yz

C(x,y,z) = 7xy + 2xz + 2yz

We're to minimize this function subject to the constraint that

xyz = V

The constraint can be rewritten as

xyz - V = 0

Using Lagrange multiplier, we then write the equation in Lagrange form

Lagrange function = Function - λ(constraint)

where λ = Lagrange factor, which can be a function of x, y and z

L(x,y,z) = 7xy + 2xz + 2yz - λ(xyz - V)

We then take the partial derivatives of the Lagrange function with respect to x, y, z and λ. Because these are turning points and at the turning point, each of the partial derivatives is equal to 0.

(∂L/∂x) = 7y + 2z - λyz = 0

λ = (7y + 2z)/yz = (7/z) + (2/y) (eqn 1)

(∂L/∂y) = 7x + 2z - λxz = 0

λ = (7x + 2z)/xz = (7/z) + (2/x) (eqn 2)

(∂L/∂z) = 2x + 2y - λxy = 0

λ = (2x + 2y)/xy = (2/y) + (2/x) (eqn 3)

(∂L/∂λ) = xyz - V = 0

We can then equate the values of λ from the first 3 partial derivatives and solve for the values of x, y and z

(eqn 1) = (eqn 2)

(7/z) + (2/y) = (7/z) + (2/x)

(2/y) = (2/x)

y = x

Also,

(eqn 1) = (eqn 3)

(7/z) + (2/x) = (2/y) + (2/x)

(7/z) = (2/y)

z = (7y/2)

Hence, at the point where the box has minimal area,

y = x,

z = (7y/2) = (7x/2)

We can then substitute those into the constraint equation for y and z

xyz = V

x(x)(7x/2) = V

(7x³/2) = V

x³ = (2V/7)

x = ∛(2V/7)

y = x = ∛(2V/7)

z = (7x/2) = 3.5 [∛(2V/7)]

The values of x, y and z in terms of the volume that minimizes the cost function are

{x,y,z} = {∛(2V/7), ∛(2V/7), 3.5[∛(2V/7)]}

Hope this Helps!!!

7 0
3 years ago
Answere Number 6,7,8,9,10,11,12 PLEASE help :)
stepan [7]
6.)17/12 7.)9/10 8)1 1/6 9.)1 3/8 10.)7/6 11.)7/10 12.)1 1/8
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Convert 83% into a decimal<br> can you guy help me to do that
PilotLPTM [1.2K]
To convert a percentage to decimal form, you need to divide the number in the percent by 100. In reality, that just looks like moving the decimal point to the left two places.

83% / 100 = 0.83

83% in decimal form is 0.83.
Hope that helped! =)
6 0
3 years ago
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