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maw [93]
3 years ago
14

I need help with this if you’re right I will mark you as brainlest

Mathematics
2 answers:
liraira [26]3 years ago
5 0

Answer:

try 1.8 or .18

Step-by-step explanation:

pantera1 [17]3 years ago
4 0

Step-by-step explanation:

Since,

ABC~ABE

THEREFORE AB~AD

6~12

SINCE AD IS TWICE AB

THEREFORE THE TRIANGLE ADE WILL BE TWICE THE ABC ,IN PERIMETER.

THEREFORE

BC*2=DE

0.9*2=DE(h)

DE=1.8

h=1.8

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The product of 16 and the variable of p
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OM , ON and OP are the angle bisectors of ∠AOB, ∠BOC, and ∠COD respectively. ∠AOD and ∠BOE are straight angles.
Orlov [11]

Find m∠BOC, if m∠MOP = 110°.

Answer:

m∠BOC= 40 degrees

Step-by-step explanation:

A diagram has been drawn and attached below.

  • OM bisects AOB into angles x and x respectively
  • ON bisects ∠BOC into angles y and y respectively
  • OP bisects ∠COD into angles z and z respectively.

Since ∠AOD is a straight line

x+x+y+y+z+z=180 degrees

2x+2y+2z=180^\circ

We are given that:

m∠MOP = 110°.

From the diagram

∠MOP=x+2y+z

Therefore:

x+2y+z=110°.

Solving simultaneously by subtraction

2x+2y+2z=180^\circ

x+2y+z=110°.

We obtain:

x+z=70°

Since we are required to find ∠BOC

∠BOC=2y

Therefore from x+2y+z=110° (since x+z=70°)

70+2y=110

2y=110-70

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Therefore:

m∠BOC= 40 degrees

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Alex787 [66]

Answer:

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Step-by-step explanation:

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