All categories

3 years ago

Which transformations will alter the location of the vertex?

Mathematics

1 answer:

VashaNatasha [74]3 years ago

4 0

Answer:

reflection

transition left / right are the location of the vertex

You might be interested in

Someone help factor. This for me

Ksenya-84 [330]

Answer:

w(4 - 11w)

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Find the measure of angles 1, 2, 3, 4, 5 ,6 and 7

vivado [14]

Answer:

angle1=70

angle2=65

angle4=115

angle7=45

angel6=45

angle5=45

Step-by-step explanation:

110+angle1 = 180

angle1 =180-70

angle1 = 70

115+angle2=180

angle2=180-115

angle2=65

angle4=115 because lines are parallel

angle1+angle2+angle7=180 because triangle

70+65+angle7=180

135+angle7=180

angle7=180-135

angle7=45

angel6=45

angle5=45

8 0

2 years ago

What is the product of 2a-7/a* 3a^2/2a^2-11a+14

Vera_Pavlovna [14]

Answer:

B. 3a/a-2

Step-by-step explanation: according to e2020

8 0

2 years ago

Read the problem and solve.

gavmur [86]

442 is the answer thedjfbbxhcbdhx

8 0

2 years ago

5. Mis the midpoint of CD. C has coordinates (-1,-1) and

lana66690 [7]

Answer/Step-by-step Explanation:

4. Midpoint (M) of AB, for A(-2, -3) and B(1, 2) is given as:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Let $A(-2, -3) = (x_1, y_1)$

$B(1, 2) = (x_2, y_2)$

Thus:

$M(\frac{-2 + 1}{2}, \frac{-3 + 2}{2})$

$M(\frac{-1}{2}, \frac{-1}{2})$

5. Given M(3, 5) as midpoint of CD, and C(-1, -1),

let $C(-1, -1) = (x_2, y_2)$

$D(?, ?) = (x_1, y_1)$

$M(3, 5) = (\frac{x_1 +(-1)}{2}, \frac{y_1 +(-1)}{2})$

Rewrite the equation to find the coordinates of D

$3 = \frac{x_1 - 1}{2}$ and $5 = \frac{y_1 - 1}{2}$

Solve for each:

$3 = \frac{x_1 - 1}{2}$

$3*2 = \frac{x_1 - 1}{2}*2$

$6 = x_1 - 1$

$6 + 1= x_1 - 1 + 1$

$7 = x_1$

$x_1 = 7$

$5 = \frac{y_1 - 1}{2}$

$5*2 = \frac{y_1 - 1}{2}*2$

$10 = y_1 - 1$

$10 + 1= y_1 - 1 + 1$

$11 = y_1$

$y_1 = 11$

Coordinates of D is (7, 11)

7 0

2 years ago