Find the volume please

Which of the following values are in the range of the function graphed below

expeople1 [14]

Answer:

Range of the given function = -4

Step-by-step explanation:

Range is the set of output values.

In a graph, the set of x-values of the function is know as domain and the set of y-values of the function is known as range.

In the graph red line represents the function.

From the given graph it is clear that the function is defined from x=-1 to x=4.

For each value of x the y-value is -4.

Hence, the range of the function is -4.

4 0

3 years ago

Why is adding 3/9 and 6/9 different from multpying the two fractions? Explain

tankabanditka [31]

<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ When you add fractions, you have to have the same denominator whereas, when you multiply them, you don't have to. (In this case the denominators are already the same.) Also, multiplying the fractions would make the result smaller whereas adding them would make it larger.

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

4 0

3 years ago

In 2010, a city's population was 1,405,233 and it was decreasing at a rate of 1.1%. At this rate when will the city's population

frez [133]

The equation
                                            P(t) = 1405233 * (1 - 0.011)^(t)
models the population at t years after 2010. Then, when P(t) = 1,200,000, we have
                                 1200000 = 1405233 * (0.989)^t
                                  (0.989)^t = 1200000/1405233
                                                t = log(1200000/1405233)/log(0.989)
                                                t = 14.27 years
This means 14.27 years after 2010. Therefore, the answer to this question is 2024.

7 0

3 years ago

Find the sum of the geometric series 512+256+ . . .+4

mario62 [17]

$\bf 512~~,~~\stackrel{512\cdot \frac{1}{2}}{256}~~,~~...4$

so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?

$\bf n^{th}\textit{ term of a geometric sequence}\\\\a_n=a_1\cdot r^{n-1}\qquad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\a_n=+4\end{cases}$

$\bf 4=512\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{4}{512}=\left( \cfrac{1}{2} \right)^{n-1}\\\\\\\cfrac{1}{128}=\left( \cfrac{1}{2} \right)^{n-1}\implies \cfrac{1}{2^7}=\left( \cfrac{1}{2} \right)^{n-1}\implies 2^{-7}=\left( 2^{-1}\right)^{n-1}\\\\\\(2^{-1})^7=(2^{-1})^{n-1}\implies 7=n-1\implies \boxed{8=n}$

so is the 8th term, then, let's find the Sum of the first 8 terms.

$\bf \qquad \qquad \textit{sum of a finite geometric sequence}\\\\S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad \begin{cases}n=n^{th}\ term\\a_1=\textit{first term's value}\\r=\textit{common ratio}\\----------\\r=\frac{1}{2}\\a_1=512\\n=8\end{cases}$

$\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020$

7 0

3 years ago

Write an equation or a proportion to solve.<br> What number is 24% of 80?

Pepsi [2]

Answer:

19.20

Step-by-step explanation:

24%×80 = 24×80/100 = 1920/100 = 19.20

5 0

3 years ago

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