There you go!!! Hope I helped :)
Answer:
The equation of the line would be D) y - 7 = -3(x -5)
Step-by-step explanation:
In order to find this, we must first start with the base form of point-slope form.
y - y1 = m(x - x1)
Now we put the slope in for m and the point in for (x1, y1)
y - 7 = -3(x - 5)
Answer:
2.069x10^3
Step-by-step explanation:
Move the decimal places.
Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer: A
Step-by-step explanation:
just took it
