Answer:
A red 5 is chosen from the deck. The card is put back into the deck and the a red card is chosen.
Step-by-step explanation:
An independent event is one whose outcome is not dependent on any other event. There are two types of cards in the deck. If a red card is selected it will be from the series 1 - 20, if the card is put back into deck and then again a red card is selected it will be again from the series 1 - 20. This is an independent event since its outcome is same irrespective of the events.
Answer:
a. After the first bounce, the ball will be at 85% of 8 ft. After 2 bounces, it'll be at 85% of 85% of 8 feet. After 3 bounces, it'll be at (85% of) (85% of) (85% of 8 feet). You can see where this is going. After n bounces the ball will be at

b. After 8 bounces we can apply the previous formula with n = 8 to get

c. The solution to this point requires using exponential and logarithm equations; a more basic way would be trial and error using the previous
increasing the value of n until we find a good value. I recommend using a spreadsheet for that; the condition will lead to the following inequality:
Let's first isolate the fraction by dividing by 72.
Now, to get numbers we can plug in a calculator, let's take the natural logarithm of both sides:
. Now the two quantities are known - or easy to get with any calculator, replacing them and solving for n we get:
Now, since n is an integer - you can't have a fraction of a bounce after all, you pick the integer right after that, or n>27.
The answer to this question would be: supply
Supply will influence the current price of the market. When the supply increase, the cost will be decreased because it will be easier to find the product. When the supply decreased, the price will be increased because the product will be harder to find.
Answer:
a) Option C) The score was 2.49 standard deviations higher than the mean score in the class.
b) 2.3%
Step-by-step explanation:
a) We are given that the distribution of test grades is a bell shaped distribution that is a normal distribution.
Formula:


Option C) The score was 2.49 standard deviations higher than the mean score in the class.
b) The z-score for a particular score is -2.
We have to evaluate
P(z < -2)
Calculating the value from normal z-table.

Thus, 2.3% of of the class scored lower than my friend.