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frutty [35]
3 years ago
7

1. A given binomial distribution has a mean of 153.1 and a standard deviation of 18.2. Would a value of 187 be considered usual

or
unusual? Why?
A. Unusual, because the result is less than the maximum usual value.
B. Usual, because the result is less than the minimum usual value.
C. Unusual, because the result is greater than the maximum usual value.
D. Usual, because the result is between the minimum and maximum usual values.
Mathematics
1 answer:
Triss [41]3 years ago
8 0

Answer:

Usual, because the result is between the minimum and maximum usual values.

Step-by-step explanation:

To identify if the value is usual or unusual we're going to use the Range rule of thumbs which states that most values should lie within 2 standard deviations of the mean. If the value lies outside those limits, we can tell that it's an unusual value.

Therefore:

Maximum usual value: μ + 2σ

Minimum usual value: μ - 2σ

In this case:

μ = 153.1

σ = 18.2

Therefore:

Maximum usual value: 189.5

Minimum usual value: 116.7

Therefore, the value of 187 lies within the limits. Therefore, the correct option is D.  Usual, because the result is between the minimum and maximum usual values.

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Answer

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3 years ago
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ad-work [718]
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Thepotemich [5.8K]
The correct answer are

Sue interest : 169.6061952

Bill interest: 189.9131472


B. Bill will get more interest then sue


Explain


Sue principal balance p= 2300

Interest for 3 years so t= 3

Interest is compounded yearly n= 1

R= 2.4%

A= 2300(1+2.4/100)^3 = 2300(1+0.024)^3 = 2300 x (1.024)^3 = 2469.6061952

Interest for 3 year is A-p= 2469.6061952 -2300

169.6061952





Bill principle p= 1800

Interest for 3 years t= 3

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A= 1800(1+3.4/100)^3 = 1800 (1+0.034)^3 = 1800 (1.034)^3 = 1989.9131472

Interest in 3 yrs = 1989.9131472 - 1800 =

189.9131472



For B is below

Hopefully this help you :D

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Hello,

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