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frutty [35]
3 years ago
7

1. A given binomial distribution has a mean of 153.1 and a standard deviation of 18.2. Would a value of 187 be considered usual

or
unusual? Why?
A. Unusual, because the result is less than the maximum usual value.
B. Usual, because the result is less than the minimum usual value.
C. Unusual, because the result is greater than the maximum usual value.
D. Usual, because the result is between the minimum and maximum usual values.
Mathematics
1 answer:
Triss [41]3 years ago
8 0

Answer:

Usual, because the result is between the minimum and maximum usual values.

Step-by-step explanation:

To identify if the value is usual or unusual we're going to use the Range rule of thumbs which states that most values should lie within 2 standard deviations of the mean. If the value lies outside those limits, we can tell that it's an unusual value.

Therefore:

Maximum usual value: μ + 2σ

Minimum usual value: μ - 2σ

In this case:

μ = 153.1

σ = 18.2

Therefore:

Maximum usual value: 189.5

Minimum usual value: 116.7

Therefore, the value of 187 lies within the limits. Therefore, the correct option is D.  Usual, because the result is between the minimum and maximum usual values.

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Let b=the number of boxes, c=cost of the pens
The expression that represents the total cost of the pens if a box costs 4 dollars and then she gets a 1 dollar discount for every additional box is c(b)=3b+1. We got this from the original equation c(b)=4+(4-1)(b-1). Simplify this and you will get c(b)=3b+1. 
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4 years ago
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Which of the models represents cars as 37 1/2 of the total vehicles?
Aleonysh [2.5K]

Answer:from my understanding it should be D I would wait for someone else to answer just in case I’m wrong.

7 0
3 years ago
Let P(1,2,1), Q(1,0,-1), R(2,2,0) be the vertices of a parallelogram with adjacent sides PQ and PR. Find the other vertex S.
ladessa [460]

Given:

The vertices of a parallelogram are P(1,2,1), Q(1,0,-1), R(2,2,0).

PQ and PR are the adjacent sides of the parallelogram.

To find:

The coordinates of vertex S.

Solution:

We know that, the diagonals of a parallelogram bisect each other.

Let the coordinates of the vertex S are (a,b,c).

In the given parallelogram PS and QR are the diagonals. It means their midpoints are same.

\left(\dfrac{1+a}{2},\dfrac{2+b}{2},\dfrac{1+c}{2}\right)=\left(\dfrac{1+2}{2},\dfrac{0+2}{2},\dfrac{-1+0}{2}\right)

\left(\dfrac{1+a}{2},\dfrac{2+b}{2},\dfrac{1+c}{2}\right)=\left(\dfrac{3}{2},\dfrac{2}{2},\dfrac{-1}{2}\right)

On comparing both sides, we get

\dfrac{1+a}{2}=\dfrac{3}{2}

1+a=3

a=3-1

a=2

Similarly,

\dfrac{2+b}{2}=\dfrac{2}{2}

2+b=2

b=2-2

b=0

And,

\dfrac{1+c}{2}=\dfrac{-1}{2}

1+c=-1

c=-1-1

c=-2

Hence, the coordinates of vertex S are (2,0,-2).

4 0
3 years ago
I need help please help me :(
Varvara68 [4.7K]

Answer:

multiplication

division

addition

subtraction

Step-by-step explanation:

8 0
3 years ago
Part A: Find the LCM of 7 and 12. Show your work. (3 points)
anyanavicka [17]

The LCM of 7 and 12 is 84 and GCF of 56 and 96 is 8, 56+96 can be written as 8(19).

<h3>What is LCM?</h3>

It is defined as the common number of two integers, which is the lowest number that is a multiple of the two or more numbers. The full name of LCM is the least common multiple.

LCM of 7 and 12:

7 can be divided by 7

Factor of 12 is 2×2×3

So the LCM = 7×2×2×3 = 84

For GCF:

We know:

GCF(56, 96) = (56×96)/LCM(56, 96)

GCF(56×96) = (56×96)/672 = 8

= (56 + 96)

= 8(7+12)

= 8(19)

Thus, the LCM of 7 and 12 is 84 and GCF of 56 and 96 is 8, 56+96 can be written as 8(19).

Learn more about the LCM here:

brainly.com/question/20739723

#SPJ1

3 0
2 years ago
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