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kykrilka [37]
3 years ago
6

Which statement is true about the function f(x)= √x?

Mathematics
2 answers:
AlexFokin [52]3 years ago
8 0

Answer:

The range of the graph is all real numbers greater than or equal to 0.

Step-by-step explanation:

we have

y=\sqrt{x}

using a graphing tool

The graph in the attached figure

step 1

Find the domain

we know that the radicand of the function must be greater than or equal to zero

so

The domain is the interval ------> [0,∞)

x\geq0

All real numbers greater than or equal to zero

step 2

Find the range

The range is the interval -----> [0,∞)

y\geq0

All real numbers greater than or equal to zero

Soloha48 [4]3 years ago
5 0

Answer:

d just took the test

Step-by-step explanation:

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In NC, Henderson County has a land area of about 375 square miles and Perquimans County has a land area of about 250 square mile
kirza4 [7]

375 mi^2         15

--------------- =  ------ = 3/2

250 mi^2        10

The ratio of the population of Henderson County to that of Perquimans is 3/2.

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3 years ago
Quadrilateral ABCD is inscribed in circle 0 What is m<A
valentinak56 [21]
We know that
 A quadrilateral is inscribed in a circle if and only if the opposite angles are supplementary. ( Inscribed Quadrilateral Theorem)
so
m∠B+m∠D=180°
2x+(3x-5)=180
5x=180+5
5x=185
x=185/5
x=37°

m∠A=x+5-----> 37+5------> 42°

the answer is
m∠A is 42°

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3 years ago
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6 0
3 years ago
A ball is projected in to the air. Its height at time t is given by the equation
Ksju [112]
The equation gives the height of the ball. That is, h is the height of the ball. t is the time. Since we are looking for the time at which the height is 8 (h=8), we need to set the equation equal to 8 and solve for t. We do this as follows:

h=-16 t^{2} +60t+1
8=-16 t^{2} +60t+1
16 t^{2} -60t-1+8=0
16 t^{2} -60t+7=0

This is a quadratic equation and as it is set equal to 0 we can solve it using the quadratic formula. That formula is:
t= \frac{-bplus minus \sqrt{ b^{2}-4ac } }{2a}
You might recall seeing this as "x=..." but since our equation is in terms of t we use "t-=..."

In order to use the formula we need to identify a, b and c.
a = the coefficient (number in front of) t^{2} = 16.
b = the coefficient of t = -60
c = the constant (the number that is by itself) = 7

Substituting these into the quadratic formula gives us:
t= \frac{-(-60)plus minus \sqrt{ (-60)^{2}-4(16)(7) } }{2(16)}
t= \frac{60plus minus \sqrt{3600-448 } }{32}
t= \frac{60plus minus \sqrt{3152 } }{32}

As we have "plus minus" (this is usually written in symbols with a plus sign over a minus sign) we split the equation in two and obtain:
t=  \frac{60+56.1426}{32} =3.63
and
t=  \frac{60-56.1426}{32} =.12

So the height is 8 feet at t = 3.63 and t=.12

It should make sense that there are two times. The ball goes up, reaches it's highest height and then comes back down. As such the height will be 8 at some point on the way up and also at some point on the way down.


3 0
3 years ago
Perform the following operations and prove closure. Show your work.<br><br> (x/x+3) + (x+2/x+5)
Westkost [7]

Answer:

\frac{2(x^{2} + 5x + 3)}{(x+3)(x+5)}

Step-by-step explanation:

We need to sum the following two expressions:

\frac{x}{x+3} + \frac{x+2}{x+5}

\frac{x(x+5) + (x+2)(x+3)}{(x+3)(x+5)}

expanding the polynomial in the numerator:

\frac{2x^{2} + 10x + 6}{(x+3)(x+5)}

\frac{2(x^{2} + 5x + 3)}{(x+3)(x+5)}

This is the most simplified form we can get:

\frac{2(x^{2} + 5x + 3)}{(x+3)(x+5)}

8 0
3 years ago
Read 2 more answers
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