we are given with the inequality
Open the parenthesis we get on left side we get
Solve this equation. the answers are listed below
1 answer:
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Answer: The system of equations is:
x + 2y + 2 = 4
y - 3z = 9
z = - 2
The solution is: x = -22; y = 15; z = -2;
Step-by-step explanation: ONe way of solving a system of equations is using the Gauss-Jordan Elimination.
The method consists in transforming the system into an augmented matrix, which is writing the system in form of a matrix and then into a <u>Row</u> <u>Echelon</u> <u>Form,</u> which satisfies the following conditions:
- There is a row of all zeros at the bottom of the matrix;
- The first non-zero element of any row is 1, which called leading role;
- The leading row of the first row is to the right of the leading role of the previous row;
For this question, the matrix is a Row Echelon Form and is written as:
or in system form:
x + 2y + 2z = 4
y + 3z = 9
z = -2
Now, to determine the variables:
z = -2
y + 3(-2) = 9
y = 15
x + 30 - 4 = 4
x = - 22
The solution is (-22,15,-2).
Compound Interest
A total of $20,000 is invested in different assets.
45% is invested in a Treasury bond for 3 years at 4.35 APR compounded annually.
For this investment, the principal is P = 0.45*$20,000 = $9,000.
The compounding period is yearly, thus the interest rate is:
i = 4.35 / 100 = 0.0435
The duration (in periods) is n = 3
Calculate the final value with the formula:
Substituting:
The second investment is a CD at 3.75% APR for 3 years compounded annually. The parameters for the calculations are as follows:
P = 15% of $20,000 = $3,000
i = 3.75 / 100 = 0.0375
n = 3
Calculating:
The third investment is in a stock plan. The initial value of the investment is
P = 20% of $20,000 = $4,000
By the end of the first year, the stock plan increased by 8%, thus its value is:
M1 = $4000 * 1.2 = $4,800
By the end of the second year, the stock plan decreased by 4$, thus the value is:
M2 = $4,800 * 0.96 = $4,608
Finally, the stock plan increases by 6%, resulting in a final balance of:
M3 = $4,608 * 1.06 = $4,884.48
Finally, the last investment is in a savings account at 2.90% APR compounded annually for 3 years (not mentioned, but assumed).
P = $20,000 - $9,000- $3,000 - $4,000 = $4,000
i = 2.90 / 100 = 0.029
n = 3
Calculating:
To summarize, the final balances for each type of investment at the end of the third year are:
Investment 1; $10,226.33
Investment 2: $3,350.31
Investment 3: $4,884.48
Investment 4: $4,358.19
Total balance: $22,819.32