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3 years ago

Why are people against saving the ozone layer?

Chemistry

1 answer:

nalin [4]3 years ago

3 0

Because they don't care and think the ozone layer is fine.

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HELP ASAP Choose three sections of the electromagnetic spectrum. Rank them in order of energy. Give an example of how they are u

hodyreva [135]

Isn’t Bambi undo hall

4 0

4 years ago

Which of the following does not involve colligative properties?

kumpel [21]

The answer is d. calcium silicide is added to liquid steel to increase the steel's ability to freeze

8 0

4 years ago

Read 2 more answers

What is a harmful role of bacteria?

zzz [600]

Answer:

sickness.

Explanation:

some bacterium cause sickness, kike a stomach bug.

6 0

4 years ago

Suppose a sodium hydroxide solution was standardized against pure solid primary standard grade KHP. If 0.4798 g of KHP required

Readme [11.4K]

Answer:

The NaOH solution has a molarity of 0.052 M

Explanation:

Step 1: Data given

Mass of KHP = 0.4798 grams

Volume of NaOH= 45.22 mL = 0.04522 L

Molar mass of NaOH = 40 g/mol

Molar mass of KHP = 204.22 g/mol

Step 2: Calculate moles of KHP

Moles KHP = mass KHP / Molar mass KHP

Moles KHP = 0.4798 grams / 204.22 g/mol

Moles KHP = 0.00235 moles

Step 3: Calculate moles of NaOH

KHP here acts as a mono-acid so, the number of moles of NaOH = number of moles KHP = 0.00235 moles

Step 4: Calculate molarity of NaOH

Molarity NaOH = moles NaOH / volume NaOH

Molarity NaOH = 0.00235 moles / 0.04522 L

Molarity NaOH = 0.052 M

The NaOH solution has a molarity of 0.052 M

6 0

4 years ago

The specific heats and densities of several materials are given below: Material Specific Heat (cal/g·°C) Density (g/cm3) Brick 0

abruzzese [7]

Answer: The change in temperature is 84.7°C

Explanation:

To calculate the change in temperature, we use the equation:

$q=mc\Delta T$

where,

q = heat absorbed = 1 kCal = 1000 Cal (Conversion factor: 1 kCal = 1000 Cal)

m = mass of steel = 100 g

c = specific heat capacity of steel = 0.118 Cal/g.°C

$\Delta T$ = change in temperature = ?

Putting values in above equation, we get:

$1000cal=100g\times 0.118cal/g^oC\times \Delta T\\\\\Delta T=\frac{1000cal}{100g\times 0.118cal/g^oC}\\\\\Delta T=84.7^oC$

Hence, the change in temperature is 84.7°C

5 0

3 years ago