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blagie [28]
3 years ago
15

A sugar that has the chemical formula C5H10O5 would be characterized as _____.

Chemistry
1 answer:
Tanya [424]3 years ago
7 0

Answer:

The answer to your question is: a. pentose

Explanation:

a) a pentose  is a monosaccharide that has 5 carbons in its structure, if we look at the question the chemical formula only has 5 carbons, then this is the right answer.

b) an oligosaccharide  is a group of 2 or more monosaccharides (till 5 or 6) then, it will have 10 or more carbons, this is not the right answer

c) a triose  is a monosaccharide that has only three carbons, this is not the right answer.

d) a hexose   is a monosaccharide that has 6 carbons, of course this answer is wrong.

e) a polysaccharide is a group of 6 or more monosaccharides, it will have 20 or more carbons, this answer is wrong.

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How many liters of 0.37 M solution can be made with 29.53 grams of lithium fluoride.<br> (LiF)?
dsp73

Answer:

V = 3.1 L      

Explanation:

Given data:

Molarity of solution = 0.37 M

Mass of LiF = 29.53 g

Volume of solution = ?

Solution:

Number of moles of LiF:

Number of moles = mass/molar mass

Number of moles = 29.53 g/ 25.94g/mol

Number of moles = 1.14 mol

Volume:

Molarity = number of moles of solute / Volume in L

0.37 M = 1.14 mol / V

V = 1.14 mol / 0.37 M

V = 3.1 L         (M = mol/L)

4 0
3 years ago
Could someone plz help me? :(
kvv77 [185]

Answer:

I think it's B " Constraints are more important than criteria ".

3 0
3 years ago
What are the products of a neutralization reaction?
vfiekz [6]
In an acid and base neutralization reaction, the products are salt and water.
3 0
2 years ago
Read 2 more answers
The data below shows the change in concentration of dinitrogen pentoxide over time, at 330 K, according to the following process
tensa zangetsu [6.8K]

Answer: a) 1.7\times 10^{-4}

b) 3.4\times 10^{-4}

Explanation:

The reaction is :

2N_2O_5(g)\rightarrow 4NO_2(g)+O_2(g)

Rate = Rate of disappearance of N_2O_5 = Rate of appearance of NO_2

Rate =  -\frac{d[N_2O_5]}{2dt} = \frac{d[NO_2]}{4dt}

Rate of disappearance of N_2O_5 = \frac{\text {change in concentration}}{time} = \frac{0.100-0.066}{200-0}=1.7\times 10^{-4}

a) Rate of disappearance of N_2O_5 = -\frac{d[N_2O_5]}{2dt}

Rate of appearance of NO_2 = \frac{d[NO_2]}{4dt}

b) Rate of appearance of NO_2 =  \frac{d[NO_2]}{dt}=2\times 1.7\times 10^{-4}}=3.4\times 10^{-4}

8 0
2 years ago
Explain why alkali metals do not form divalent ions.​
Helga [31]
Alkali metals have only one electron in their outermost energy levels , so (they can loose one electron to) they form a mono positive ion only . That's why alkali metal do not from dispositive ions .

Hope that helps:)
7 0
2 years ago
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