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3 years ago

What are the ionic bonds

Chemistry

1 answer:

zhuklara [117]3 years ago

3 0

Explanation:

Ionic bonds are bonds formed as a result of the electrostatic attraction between two species.

This bond type is an interatomic bond.
It forms when two specie with a large electronegative difference between them combines.
This is usually a metal and a non-metal.
The metal loses its valence electrons and becomes positively charged.
The non-metal gains the electron and becomes negatively charged.
An electrostatic attraction between the two specie leads to the formation of an ionic bond.
They are solids with a high melting point.
They are soluble in polar solvents.

learn more:

Ionic bonds brainly.com/question/6071838

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Type the letter of the correct answer in the blank space. The image shows the combustion of methane. Which equation represents t

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CH4 + 2O2 → CO2 + 2H2O

Explanation:

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A sample of a compound contains 0.300 mol of carbon and 1.20 mol of hydrogen. What is the empirical formula of the comp

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The number of moles of carbon and hydrogen has been given as follows:

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3 years ago

muriatic acid is the commercial name for hydrochloric acid that can be purchased from hardware stores as a solution that is 30%(

SSSSS [86.1K]

We have 30% (w/w) HCl this means :
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3 years ago

At 25°C, K = 0.090 for the following reaction. H2O(g) + Cl2O(g) equilibrium reaction arrow 2 HOCl(g) Calculate the concentration

wlad13 [49]

Answer:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.03901 mol/liter

[Cl₂O] = 0.02351 mol/liter

Explanation:

1. Chemical reaction:

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

2. Initial concentrations:

i) 1.3 g H₂O

Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol

Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter

ii) 2.2 g Cl₂O

Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol

Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter

3. ICE (Initial, Change, Equilibrium) table

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

I 0.0481 0.0326 0

C -x -x +x

E 0.0481-x 0.0326-x x

4. Equilibrium expression

$K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}$

$0.09=\dfrac{x^2}{(0.0481-x)(0.0326-x)}$

5. Solve:

$x^2=0.09(x-0.0481)(x-0.0326)\\\\0.91x^2+0.007263x-0.000141125=0$

Use the quadatic formula:

$x=\dfrac{-0.007263\pm \sqrt{(0.007263)^2-4(0.91)(-0.000141125)}}{2(0.91)}$

The positive result is x = 0.00909

Thus the concentrations are:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter

[Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter

3 0

3 years ago