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3 years ago

Chlorine gas react according to the

1 answer:

8 0

Chlorine gas reacts together with nitrogen monoxide gas according to the following equation in chemistry which is 2NO(g) + Cl2(g) à 2NOCl(g). Chlorine gas is used as a disinfectant. It is also used to keep the swimming pool away from bacteria because chlorine gas kills bacteria.

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2_PCl3 + __Cl2 →<br> __PCL5<br> What is the answer

bekas [8.4K]

Answer: 2 PCl3 + 2 Cl2 > 2 PCl5

Explanation: The factors will be 2 moles of PCl3 reacted to 2 moles of chlorine gas Cl2 and the reaction will produce 2 moles of Phosphorous pentachloride PCl5.

For the reactants 2PCl3 +2 Cl2 there will be 2P, Cl (2x3) +

(2x2) so chlorine will have 10. In the product side 2PCl5. 2 P and Cl will have (5x2)=10.

The chemical reaction will have a balance chemical equation.

3 0

3 years ago

A student placed 10.5 g of glucose (C6H12O6) in a volumetric fla. heggsk, added enough water to dissolve the glucose by swirling

aniked [119]

<u>Answer:</u> The mass of glucose in final solution is 0.420 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .........(1)

Initial mass of glucose = 10.5 g

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$\text{Initial molarity of glucose}=\frac{10.5\times 1000}{180.16\times 100}\\\\\text{Initial molarity of glucose}=0.583M$

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated glucose solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted glucose solution

We are given:

$M_1=0.583M\\V_1=20.0mL\\M_2=?M\\V_2=0.5L=500mL$

Putting values in above equation, we get:

$0.583\times 20=M_2\times 500\\\\M_2=\frac{0.583\times 20}{500}=0.0233M$

Now, calculating the mass of final glucose solution by using equation 1:

Final molarity of glucose solution = 0.0233 M

Molar mass of glucose = 180.16 g/mol

Volume of solution = 100 mL

Putting values in equation 1, we get:

$0.0233=\frac{\text{Mass of glucose in final solution}\times 1000}{180.16\times 100}\\\\\text{Mass of glucose in final solution}=\frac{0.0233\times 180.16\times 100}{1000}=0.420g$

Hence, the mass of glucose in final solution is 0.420 grams

3 0

4 years ago

Can you guys help me I really need help ! Just started this 6th grade I really need help I’m use to this

NeX [460]

Answer:

Mechanical - Freezing & Thawing, Acid Rain, Flowing Water, oxidation

Chemical - Rusting, abrasion

Explanation:

hope this helps!

5 0

3 years ago

1 CHEM QUESTION PLEASE HELP<br> What is meant by the phrase, “conservation of mass”?

Pavel [41]

It is a principle that states that mass cannot be loss or gained in a chemical reaction.

5 0

3 years ago

5. A gas with a volume of 300 Liters at 295 kPa is allowed to expand to a volume of 350 Liters. What is the final pressure insid

storchak [24]

Answer:

Explanation:

The new pressure can be found by using the formula

$P_2 = \frac{P_1V_1}{V_2} \\$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

From the question we have

$P_2 = \frac{300 \times 295}{350} \\ = 252.85714$

We have the final answer as

Hope this helps you

3 0

3 years ago