All categories

2 years ago

Describe the trend for atomic radius from left to right across a period. Use atomic

1 answer:

6 0

As you move across a period, the atomic radii decreases. ... As you move across a period, electrons are added to the same energy level while protons are also being added. The concentration of more protons creates a higher effective nuclear charge.

You might be interested in

The second-order rate constants for the reaction of oxygen atoms witharomatic hydrocarbons have been measured (R. Atkinson and J

Pepsi [2]

Answer:

A = 1,13x10¹⁰

Ea = 16,7 kJ/mol

Explanation:

Using Arrhenius law:

ln k = -Ea/R × 1/T + ln(A)

You can graph ln rate constant in x vs 1/T in y to obtain slope: -Ea/R and intercept is ln(A).

Using the values you will obtain:

y = -2006,9 x +23,147

As R = 8,314472x10⁻³ kJ/molK:

-Ea/8,314472x10⁻³ kJ/molK = -2006,9 K⁻¹

<em>Ea = 16,7 kJ/mol</em>

Pre-exponential factor is:

ln A = 23,147

A = e^23,147

I hope it helps!

6 0

2 years ago

1. This balanced equation represents a chemical reaction.

Dafna1 [17]

Answer:

combustion is the answer

5 0

2 years ago

What mass of calcium carbonate is produced when 250 mL of 6.0 M sodium carbonate is added to 750 mL of 1.0 M calcium fluoride

Savatey [412]

<u>Given:</u>

Volume of Na2CO3 = 250 ml = 0.250 L

Molarity of Na2CO3 = 6.0 M

Volume of CaF2 = 750 ml = 0.750 L

Molarity of CaF2 = 1.0 M

<u>To determine:</u>

The mass of CaCO3 produced

<u>Explanation:</u>

Na2CO3 + CaF2 → CaCO3 + 2NaF

Based on the reaction stoichiometry:

1 mole of Na2CO3 reacts with 1 moles of Caf2 to produce 1 mole of caco3

Moles of Na2CO3 present = V * M = 0.250 L * 6.0 moles/L = 1.5 moles

Moles of CaF2 present = V* M = 0.750 * 1 = 0.750 moles

CaF2 is the limiting reagent

Thus, # moles of CaCO3 produced = 0.750 moles

Molar mass of CaCO3 = 100 g/mol

Mass of CaCO3 produced = 0.750 moles * 100 g/mol = 75 g

Ans: Mass of CaCO3 produced = 75 g

7 0

3 years ago

A sample of an unknown solid is found to have a volume of 24.3 cm3 and a mass of

blondinia [14]

<h2>Answer: 8.93 g/cm³ </h2>

<h3>Explanation: </h3>

Density = mass ÷ volume

= 217.0 g ÷ 24.3 cm³

= 8.93 g/cm³

∴ the unknown sample of mass 217.0 grams and volume of 24.3 cm³ has a density of 8.93 g/cm³.

5 0

2 years ago

What are the coefficients for the reaction _Cl2O5 + _H2O → _HClO3 once it is balanced?

Eva8 [605]

It is B (1,1,2) because when you plug those numbers in, there are the same amount of elements in the reactant and product, just rearranged as the format A+B <span>→ AB, because this is a synthesis reaction.</span>

7 0

2 years ago

Read 2 more answers