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Setler [38]
3 years ago
7

1. A cupcake show makes and delivers specialized cupcakes. It will cost someone $30 for

Chemistry
1 answer:
lorasvet [3.4K]3 years ago
8 0

Answer:

2.5

Explanation:

The given costs for the purchase and delivery of the cupcakes are;

The cost of 10 cupcakes and the delivery fee = $30

The cost of 25 cupcakes and the delivery fee = $67.50

Let 'c' represent the fixed cost of delivery of the cup cakes, and let 'x' represent the cost of each cup cake, we have;

30 = 10·x + c...(1)

67.50 = 25·x + c...(2)

Subtracting equation (1) from equation (2) gives;

67.50 - 30 = 37.50 = 25·x - 10·x + c - c = 15·x

∴ x = 37.50/15 = 2.5

The cost of each cupcake, x = 2.5

(∴ The delivery fee = 30 - 10 × 2.5 = 5)

The cost of each cupcake is 2.5.

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7 0
3 years ago
Copper crystallizes in a face centered cubic lattice. if the edge of the unit cell is 351 pm what is the radius of the copper at
Troyanec [42]
Density of unit cell is mathematically expressed as
D = \frac{\text{Z  X Atomic Weight}}{\text{Avagadro's Number X a^3}}

where, Z = number of atoms/unit cell = 4 (For FCC structure)
Atomic weight of Cu = 63.5 g
a = edge length = 351 pm = 351 X 10^-10 cm
Avagadro's number = 6.023 X 10^23

∴ Density of unit cell = \frac{4X63.5}{6.023X10^2^3X(351X10^-^1^0)^3}
                                 = 9.752 g/cm3

Now, for FCC structure a = √8 r
where r = radius of Cu
∴ r = a/√8 = (351 X 10^-10)/√8 = 1.24 X 10^-8 cm = 124 pm
8 0
3 years ago
Study the picture below. <br><br><br><br><br><br>Done!! Thanks ​
myrzilka [38]

The rabbit and the girl are living things.

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5 0
3 years ago
Describe how you would prepare 500.0mL of an aqueous solution that is 30.0% isopropyl alcohol by volume
Artyom0805 [142]

Answer:

The solution can be prepared by adding 150.0 mL of isopropyl alcohol to 350.0 mL of water to make 30.0% isopropyl alcohol aqueous solution.

Explanation:

∵ The volume% of a solution = [(volume of the solute(isopropy)/(volume of the solution)] x 100.

The volume % = 30.0%, volume of the solution = 500.0 mL.

∴ Volume of the solute = (the volume% of a solution)(volume of the solution)/100 = (30.0%)(500.0 mL)/100 = 150.0 mL.

∵ The volume of solution = volume of the solute + volume of water

∴ Volume of water = volume of the solution - volume of the solute = (500.0 mL) - (350.0 mL) = 150.0 mL.

  • <em>So, the solution can be prepared by adding 150.0 mL of isopropyl alcohol to 350.0 mL of water to make 30.0% isopropyl alcohol aqueous solution.</em>
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4 years ago
Which scatterplot shows a positive association between the variables
prohojiy [21]

Answer:

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Explanation:

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