Answer:
539 kPa
Explanation:
Pressure equals density times acceleration of gravity times depth.
P = ρgh
Water has a density of 1000 kg/m³, and acceleration of gravity is 9.8 m/s².
P = (1000 kg/m³) (9.8 m/s²) (55.0 m)
P = 539,000 Pa
P = 539 kPa
Answer:
Hey there
Your answer should be Joules, Watts, and J/s.
The joule
The joule (pronounced jool) is a derived unit of energy in the International System of Units. It is equal to the energy transferred to (or work done on) an object when a force of one newton acts on that object in the direction of the force's motion through a distance of one metre (1 newton-metre or N⋅m). It is also the energy dissipated as heat when an electric current of one ampere passes through a resistance of one ohm for one second. It is named after the English physicist James Prescott Joule (1818–1889).
The Watt
The watt (symbol: W) is a unit of power or radiant flux. In the International System of Units (SI), it is defined as a derived unit of (in SI base units)[1][2] 1 kg⋅m2⋅s−3 or, equivalently,[3] 1 joule per second (J/s). It is used to quantify the rate of energy transfer. The watt is named after James Watt (1736-1819), an 18th-century Scottish inventor.
I beg your parden
If I am correct may I please have the brainly
so first your going to use v=Δd/Δt given you the answer 80 i think that's right
Answer:
28 J
Explanation:
Mechanical energy is the sum of kinetic and potential energy in an object that is used to do work. In other words, it is energy in an object due to its motion or position, or both.
In physics, mechanical energy (Emech) is the energy associated with the motion and position of an object usually in some force field.
Therefore:
ME = KE + PE = 25 + 3 = 28 J
The general formula for the frequency of the nth-harmonic of the column of air in the tube is given by
where f1 is the fundamental frequency.
In our problem, we have two harmonics, one of order n and the other one of order (n+1) (because it is the next higher harmonic), so their frequencies are
so their difference is
So, the difference between the frequencies of the two harmonics is just the fundamental frequency of the column of air in the tube, which is:
