Given the reaction: 2H₂ + O₂ → 2H₂O The total number of grams of O₂ needed to produce 54 grams of water is _________.
1 answer:
Answer : The mass of needed are, 48 grams.
Explanation :
First we have to calculate the moles of
Now we have to calculate the moles of
The given balanced chemical reaction is:
From the reaction, we conclude that
As, 2 mole of produces from 1 mole of
So, 3 mole of produces from
mole of
Now we have to calculate the mass of
Molar mass of = 32 g/mole
Therefore, the mass of needed are, 48 grams.
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Answer:
The 200 grams of carbohydrate would this convert to 800 kcals in a day.
Explanation:
Carbohydrates are the source of energy. The metabolism of 1 gram of carbohydrates gives 4 kcals of energy.
If 200 grams of carbohydrate is consumed in a day, then the energy provided by it is:-
<u>The 200 grams of carbohydrate would this convert to 800 kcals in a day.</u>
The question is incomplete. There's missing the image, which is shown below.
Answer:
Volume of O₂ = 6 L, volume of mixture: 18 L, volume of H₂O = 12 L, molecule volume of H₂O = 0.667 molecule/L
Explanation:
The reaction between hydrogen gas and oxygen gas to form water is:
2H₂(g) + O₂(g) → 2H₂O(g)
So, for 1 mol of O₂ is necessary 2 moles of H₂ form 2 moles of H₂O. As the images below there's 8 molecules of H₂, 4 molecules of O₂, 12 molecules in the mixture, and 8 molecules of H₂O. Thus, there are stoichiometric values.
All the images are at the same temperature and pressure, so, by the ideal gas law:
PV= nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
The number of moles and molecules are related, so let's substitute it in the equation. For the H₂:
P*12 = 8*RT
RT/P = 12/8 = 1.5
Thus, for O₂:
PV= nRT
V = n*(RT/P)
V = 4*1.5 = 6 L
For the mixture:
V = 12*1.5 = 18 L
For H₂O:
V = 8*1.5 = 12 L
The molecule volume is the number of molecules divided by the volume they occupy, thus for water: 8/12 = 0.667 molecules/L
