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djverab [1.8K]
3 years ago
7

What is the function of the phytoplankton in the ocean ecosystem

Chemistry
1 answer:
Nitella [24]3 years ago
7 0

Phytoplankton is a type of micro algae. This creature is similar to the other plants in the ocean biome. But what makes it special is the fact that it is the main produce in the food web. The plant is so small that it is impossible to see it with the naked eye.

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However, that doesn’t remove the fact that phytoplankton contains a huge amount of chlorophyll. Here are the 13 Function of the Phytoplankton in Ocean Ecosystem. Find out what makes this small plant so crucial to the ocean

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A triple beam balance is used to measure mass
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2 years ago
Read 2 more answers
Maize, man, Goat, is an example of a food chain<br>true or false​
Lina20 [59]

Answer:

False

Explanation:

The correnct chain is labeled Maize, Goat, Man.

8 0
3 years ago
the enthalpy of vaporization of an roganic alchol is 35.3 kJ/mol at the boiling pointof 64.2 C calculate the entropy change for
bonufazy [111]

Answer:

Explanation:

s=h/t

=35.3/64.2(c)

=35.3/337.2(k)

=0.104

3 0
1 year ago
X-rays had a frequency of about 3x10^18 determine it's wavelength (in nm) and energy per photon
Serggg [28]

Answer:

E = 19.89×10⁻¹⁶ J

λ = 1×10⁻¹ nm

Explanation:

Given data:

Frequency of xray = 3×10¹⁸ Hz

Wavelength of xray = ?

Energy of xray = ?

Solution:

speed of wave = wavelength × frequency

speed = 3×10⁸ m/s

3×10⁸ m/s  = λ ×3×10¹⁸ s⁻¹

λ = 3×10⁸ m/s  / 3×10¹⁸ s⁻¹

λ = 1×10⁻¹⁰m

m to nm:

λ = 1×10⁻¹⁰m×10⁹

λ = 1×10⁻¹ nm

Energy of x-ray:

E = h.f

h = plancks constant = 6.63×10⁻³⁴ Js

by putting values,

E = 6.63×10⁻³⁴ Js ×3×10¹⁸ s⁻ ¹

E = 19.89×10⁻¹⁶ J

7 0
2 years ago
Calculate the mass of khc8h4o4 that reacts with 15 ml of the naoh solution
dlinn [17]
The balanced chemical reaction would be:

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The concentration of the NaOH is equal 0.1 M. We use this and the volume given above to determine the mass of KH</span>C8H4O4. We do as follows:

0.1 mol / L NaOH (.015 L) ( 1 mol KHC8H4O4 / 1 mol NaOH) (204 g / 1 mol) = 0.306 g KHC8H4O4


6 0
3 years ago
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