Answer:
Q = 1102.5 j
Explanation:
Given data:
Mass of chloroform = 25 g
Initial temperature = 67.0°C
Final temperature = 112.0°C
Heat absorbed = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Specific heat capacity of chloroform = 0.98 j/g.°C
ΔT = T2-T1
ΔT = 112.0°C - 67.0°C
ΔT = 45°C
Q = m.c. ΔT
Q = 25 g × 0.98 j/g.°C × 45°C
Q = 1102.5 j
