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kirza4 [7]
4 years ago
12

Need some help with this math

Mathematics
2 answers:
Ostrovityanka [42]4 years ago
8 0

Answer:

$44

Step-by-step explanation:

Let's set a proportion.

$40 - 100%

$x   - 10%

(40 x 10) : 100= $4.

We found out how much is that 10% BUT Steve payed this amount on top of $40. So, $40+$4= <u>$44.</u>

So select 44

iren2701 [21]4 years ago
5 0

Answer:

4 $ on tax and 36 $ on purchase.hope this helps

Step-by-step explanation:

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masya89 [10]

Answer:

b is the correct answer for apex users

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3 years ago
Read 2 more answers
1. The mZRST is 37º. The mZRSV is 58°. What is the mZTSV? R T s​
VMariaS [17]

Answer:

-21

the answer isss -21

3 0
3 years ago
Solve for x: 4 − (x + 2) &lt; −3(x + 4)
jeyben [28]
4 - (x+2) < -3(x+4)

4 -1(x) -1(2) < -3(x) -3(4)
4 - x - 2 < -3x -12
 <u>  +3x        +3x      </u>
<u />2 + 2x    <   -12
<u>-2                   -2    
</u>      2x     < -14
<u /> <u>     ÷2          ÷2    </u>
        x      < -7

assume that x = -8

4 - (-8 + 2) < -3(-8 + 4)
4 - (-6) < -3(-4)
4 + 6 < 12
10 < 12  the inequality is true.
8 0
3 years ago
Charles is 20% heavier than Edith. If Charles weighs 60kg, what is Edith's weight?​
ddd [48]

Charles' weight = Edith's weight + 20% of Edith's weight

We'll use a variable to represent Edith's weight, x.

The decimal form of 20% is 0.2.

60 = x + 0.2x

60 = 1.2x

x = 50

Edith's weight is 50kg.

Hope this helps!

4 0
2 years ago
A magazine claims that the mean amount spent by a customer at Burger Stop is greater than the mean amount spent by a customer at
netineya [11]

Answer: Option "B" is correct.

Step-by-step explanation:

Since we have given that

α= 0.10

Let the population variances are equal and samples are random and independent.

Let \bar{x} be the mean amount spent by a customer at Burger Stop.

Let \mu be the mean amount spent by customer at Fry World.

So, it has given that

the mean amount is spent by a customer at Burger stop is greater than the mean amount spent by a customer at Fry World.

So, Hypothesis would be :

H_0:\bar{x}=\mu\\\\H_1:\bar{x}>\mu

Hence, Option "B" is correct.

3 0
3 years ago
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