Assumptions: 1. Equilibrium has been reached for the allele proportions 2. Absence of <span>evolutionary influences such as </span>mate choice<span>, </span>mutation<span>, </span>selection<span>, </span>genetic drift<span>, </span>gene flow<span> and </span>meiotic drive<span>. </span> Defining L=long stem, l=short stem, and L is dominant over l. f(x) = frequency of allele x (expressed as a fraction of population) Then the Hardy-Weinberg equilibrium law applies: p^2+2pq+q^2=1 where f(LL)=p^2 f(Ll)=2pq f(ll)=q^2
Given f(ll)=0.35=q^2, we have q=sqrt(0.35)=0.591608 p=1-q=0.408392 => f(Ll) =2pq =2*0.408392*0.591608=0.483216 = proportion of heterozygous population
Answer: percentage of heterozygous population is 48.32%
I think the correct answer from the choices listed above is option D. Simple diffusion is the cell transport that allows small molecules to move from an area of higher concentration to an area of lower concentration without energy being <span>required from the cell.</span>
