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taurus [48]
3 years ago
11

Tammy buys a 4-gigabyte memory card for her camera. Dijonea buys a memory card with twice as much storage as Tammy’s. One gigaby

te is 1,024 megabytes. How many megabytes of storage does Dijonea have on her memory card?
Mathematics
1 answer:
tigry1 [53]3 years ago
6 0

Answer:

Dijonea have 8192  megabytes on her memory card

Step-by-step explanation:

Capacity of Tammy's memory card =  4-gigabyte

given that Dijonea buys a memory card with twice as much storage as Tammy’s

Thus,

Capacity of Dijonea's memory card =  2*Capacity of Tammy's memory card

Capacity of Dijonea's memory card =  2*4-gigabyte = 8-gigabyte

Given that

1 gigabyte = 1,024 megabytes

we have to find value of 8 gigabyte in terms of megabytes

for that we multiple both side in above equation by 8

1 *8 gigabyte = 1,024 *8 megabytes

8 gigabyte = 8192  megabytes

Thus, Dijonea have 8192  megabytes on her memory card

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Paladinen [302]

Answer:

Therefore the age of paint is 8915.78 years.

Step-by-step explanation:

Given that, the paint contain 34 % of the original carbon-14.

The exponential decay model for carbon-14 is

A=A_0e^{-0.000121t}

A= Remaining amount of carbon.

A_0 = initial amount of carbon.

Here A= 34% of A_0 =\frac{34}{100}A_0

\therefore \frac{34}{100}A_0=A_0e^{-0.000121t}

\Rightarrow \frac{34}{100}=e^{-0.000121t}

Taking ln both sides

\Rightarrow ln|\frac{34}{100}|=ln|e^{-0.000121t}|

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Therefore the age of paint is 8915.78 years.

7 0
3 years ago
Select the correct answer.
tigry1 [53]

Answer:

We can be 95% certain that the sample mean will fall within $44.87 and $46.93

Step-by-step explanation:

Empirical Rule:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

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The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Mean $45.90, standard deviation $10.31.

Sample:

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45.90 + 2*0.5155 = $46.93

We can be 95% certain that the sample mean will fall within $44.87 and $46.93

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