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rjkz [21]
3 years ago
7

2) There are 500 calories in 5 servings of Sour

Mathematics
1 answer:
ankoles [38]3 years ago
7 0
There are 100 calories per serving and there a 800 calories in 8 servings.
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The value 14 is an extraneous solution, so the equation has no real solutions. Complete the sentence below. You can tell that th
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Principal, positive                          

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Use synthetic division to evaluate (3x2 − 6x + 3) ÷ (x − 1). 3x − 9 3x2 − 3x 3x − 3 3x2 − 6
Viefleur [7K]

Answer:

\frac{\left(3x^2-6x+3\right)}{\left(x-1\right)3x-93x^2-3x^3x-33x^2-6}: -\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}
\frac{3x^2-6x+3}{\left(x-1\right)\cdot \:3x-126x^2-3x^3x-6}
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-\frac{\left(x-1\right)^2}{x^4+41x^2+x+2}

3 0
2 years ago
PLEASE HELP! I NEED TO GET THIS DONE SOON!
tensa zangetsu [6.8K]

Answer:6

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In a circle, a radius perpendicular to a chord bisects the chord. So BC = CA BC = 6 (given) x (or AC) = 6 Answer = 6. Tell me if I was right. Thanks.

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3 years ago
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last year,about 2400 people particapted ina local Fourth of July parade. This year,about 3200 people participated. What was the
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6 0
3 years ago
Can anyone help me out on this question?
svp [43]

Firstly , we will check continuity at x=1

we can use method

Suppose, f(x) is continuous at x=c

then it must satisfy

\lim_{x \to c} f(x)=f(c)

\lim_{x \to 1} f(x)=f(1)

firstly , we can find limit

\lim_{x \to 1-} f(x)=  \lim_{x \to 1-}(x+3)=1+3=4

\lim_{x \to 1+} f(x)=  \lim_{x \to 1-}(3x+1)=3*1+1=4

so, we get

\lim_{x \to 1} f(x)= 4

now, we can find f(1)

f(1)=3*1+1=4

so, we got

\lim_{x \to 1} f(x)=f(1) =4

so, this is continuous at x=1

Hence , option-D...........................Answer

5 0
3 years ago
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