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zzz [600]
2 years ago
6

A motorboat embarks on a trip, heading downstream in a river in which the current flows at a rate of 1.5m/s. After 30.0 minutes,

the boat has traveled a distance of 24.3 km downstream. How long will it take the boat to travel upstream to its original point of embarkation
Physics
1 answer:
Natali5045456 [20]2 years ago
3 0

Answer:

t=2413s

Explanation:

From the question we are told that:

Velocity v=1.5m/s

Time t=30min=>30*60=>1800

Distance d=24.3km

Generally the Newton's equation for Speed going down the stream is mathematically given by

 v + u = \frac{d}{t}

 1.5+v=frac{24300}{1800}

 v=12m/s

Therefore

 v + u = \frac{d}{t}

 t=\frac{24300}{12-1.5}

 t=2413s

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Kruka [31]

Answer:

The one with equal forces on both sides, D is your answer

Explanation:

A, 5 and 10 No

B 13 and 8 no

C 5 and 8 no

D 6 and 6 YES

3 0
2 years ago
motorcycle accelerates from rest to a final velocity of 27 m/s in 9 seconds. What is its acceleration?
Vedmedyk [2.9K]

Answer:

3 m/s squared

Explanation:

The formula you use is Vf= Vi + at. You rearrange it to a= Vf - Vi/t. The Vf is 27m/s. The Vi is 0m/s and the t is 9s. Cross out Vi since it’s zero and you’re left with a= 27m/s divided by 9s, which equals 3

5 0
2 years ago
What scientific device fascinated Newton as a Boy?
Wittaler [7]

Answer:

As a boy, Sir Isaac Newton was fascinated by a Windmill.

A drawing of a Windmill, which many believe to have been sketched by the young Newton over three an half centuries ago was discovered in his childhood home on a wall.

Cheers!

7 0
3 years ago
Sam, whose mass is 78 kg , stands at the top of a 11-m-high, 110-m-long snow-covered slope. His skis have a coefficient of kinet
Valentin [98]

Answer:

v = 8.09   m/s

Explanation:

For this exercise we use that the work done by the friction force plus the potential energy equals the change in the body's energy.

Let's calculate the energy

       

starting point. Higher

         Em₀ = U = m gh

final point. To go down the slope

         Em_f = K = ½ m v²

The work of the friction force is

         W = fr L cos 180

to find the friction force let's use Newton's second law

Axis y

        N - W_y = 0

        N = W_y

X axis

        Wₓ - fr = ma

let's use trigonometry

        sin  θ = y / L

         sin θ = 11/110 = 0.1

         θ = sin⁻¹  0.1

          θ = 5.74º

         sin 5.74 = Wₓ / W

         cos 5.74 = W_y / W

         Wₓ = W sin 5.74

         W_y = W cos 5.74

the formula for the friction force is

         fr = μ N

         fr = μ W cos θ

Work is friction force is

         W_fr = - μ W L cos θ  

Let's use the relationship of work with energy

        W + ΔU = ΔK

         -μ mg L cos 5.74 + (mgh - 0) = 0  - ½ m v²

        v² = - 2 μ g L cos 5.74 +2 (gh)

        v² = 2gh - 2 μ gL cos 5.74

let's calculate

        v² = 2 9.8 11 - 2 0.07 9.8 110 cos 5.74

        v² = 215.6 -150.16

        v = √65.44

        v = 8.09   m/s

6 0
3 years ago
What type of atom is K2CO3
My name is Ann [436]
<span>Potassium carbonate (K2C03) is white salt and is often </span>found damp. It is soluble in water which makes a strong concoction. Hope this helps.
4 0
3 years ago
Read 2 more answers
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