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3 years ago

How does the weight of a rocket affect the height and distance?

1 answer:

6 0

If the rocket it heavy and tall the distance wouldn't go very far but if the rocket was little and had no weight on it, it would go farther than the heavier one because of density/mass in the rocket

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Can someone please answer this, ill give you brainliest and your earning 50 points.

Aleonysh [2.5K]

Answer:

Good morning! It's D. all of the above

Explanation:

Social backgrounds, culture, politics, education and economic reasoning might equally contribute to uncontrolled settlements. People live in disaster-prone areas partly for economic reasons. In the case of Semarang, where tidal flooding submerges houses, people stay due to economic factors.

Plus I took the test and got it right

_AnnieTheDreamGirl, 3/10/2022

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2 years ago

NEED ANSWER NOW PLZ!!

ira [324]

Answer:

Explanation:

A beta particle is formed when a neutron changes into a proton and a high-energy electron. The proton stays in the nucleus but the electron leaves the atom as a beta particle.

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3 years ago

Be sure to answer all parts. Without stratospheric ozone (O3), harmful solar radiation would cause gene alterations. Ozone forms

Ratling [72]

Answer:

for C-Cl bond $\lambda_1=3.66\times 10^{-9}\ m$

for O-O bond $\lambda_2=2.43\times 10^{-9}\ m$

Explanation:

We have the bond enegy for C-Cl, $BE_1=327\ kJ.mol^{-1}= 327000\times 1.66\times 10^{-22}\ J\ per\ molecule$

bond enegy for C-Cl, $BE_2=494\ kJ.mol^{-1}= 494000\times 1.66\times 10^{-22}\ J\ per\ molecule$

Now as we know the energy of electromagnetic waves is given by:

$E=h.\nu$

here E = BE

Then for C-Cl:

$327000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_1$

$\nu_1=8.18733\times 10^{16}\ Hz$

Now wavelength:

$\lambda_1=\frac{c}{\nu_1}$

$\lambda_1=\frac{3\times 10^8}{8.18733\times 10^{16}}$

$\lambda_1=3.66\times 10^{-9}\ m$

For O2:

$494000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_2$

$\nu_2=1.236863\times 10^{17}\ Hz$

Now wavelength:

$\lambda_2=\frac{c}{\nu_2}$

$\lambda_2=\frac{3\times 10^8}{1.236863\times 10^{17}}$

$\lambda_2=2.43\times 10^{-9}\ m$

8 0

3 years ago

The range of temperatures on earth is much less than the range in temperatures on mercury, in part due to the presence of oceans

Feliz [49]

False, the real reason is the inconsistency of how far away the sun is

8 0

3 years ago

Three deer, A, B, and C, are grazing in a field. Deer B is located 62m from deer A at an angle of 51° north of West. Deer C is l

Anna71 [15]

Set deer A's position to be the origin. Let $c$ be the distance from deer A to deer C. We're given that deer B is 95 m away from deer C, which means the length of the vector $B-C$ is 95 (or $C-B$ ). Then

$|B-C|^2=(B-C)\cdot(B-C)=B\cdot B-2B\cdot C+C\cdot C=|B|^2-2B\cdot C+|C|^2$

$|B-C|^2=|B|^2-2|B||C|\cos(180-77-51)^\circ+c^2$

$95^2=62^2-2(62)(c)\cos52^\circ+c^2$

$c^2-124\cos52^\circ c-5181=0\implies c=120\,\mathrm m$

8 0

4 years ago