Answer:
Molarity is halved when the volume of solvent is doubled.
Explanation:
Using the dilution equation (volume 1)(molarity 1)=(volume 2)(molarity 2), we can demonstrate the effects of doubling volume.
Suppose the starting volume is 1 L and the starting molarity is 1 M, and doubling the volume would make the final volume 2 L.
Plugging these numbers into the equation, we can figure out the final molarity.
(1 L)(1 M)=(2 L)(X M)
X M= (1 L x 1 M)/(2 L)
X M= 1/2 M
This shows that the molarity is halved when the volume of solvent is doubled.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
b
![r = \frac{ k [NO_2]^2 [F_2]}{[NO_2F]}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B%20k%20%5BNO_2%5D%5E2%20%5BF_2%5D%7D%7B%5BNO_2F%5D%7D)
Explanation:
From the question we are told that
The formation mechanism is
The overall balanced equation is
We combined the first reactant and the last product and the balanced the number of mole
The observable rate law is
This rate law is derived from the balanced chemical equation
Answer:
18
Explanation:
the numbers at the top tell you
The temperature in kelvin does 60.5 liters of sulfur dioxide occupy if there are 2.5 mole at 0.75 atm is 221.07 kelvin
Explanation
This is calculated using ideal gas equation, that is PV=nRT
where, P(pressure) = 0.75 atm
V(volume) = 60.5 L
n(moles) = 2.5 mole
R( gas constant) = 0.0821 L.atm/mol.k
T(temperature =?
by making T the subject of the formula
T is therefore =Pv/nR
T= (0.75 atm x 60.5 L) / ( 2.5 molex 0.0821 L.atm/mol.K) = 221.07 kelvins
