Answer:
1.09 L
Explanation:
There is some info missing. I think this is the original question.
<em>Calculate the volume in liters of a 0.360 mol/L barium acetate solution that contains 100 g of barium acetate. Be sure your answer has the correct number of significant digits.</em>
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The molar mass of barium acetate is 255.43 g/mol. The moles corresponding to 100 grams are:
100 g × (1 mol/255.43 g) = 0.391 mol
0.391 moles of barium acetate are contained in an unknown volume of a 0.360 mol/L barium acetate solution. The volume is:
0.391 mol × (1 L/0.360 mol) = 1.09 L
Answer:
The answer is the solution containing the 90g of water.
Explanation:
Because both solutions have the same amount of the sodium chloride, the concentration would be the same if they both had the same amount of water.
Because the second solution has less water, there is more of the sodium chloride per each drop of water.
I hope this helps :)
It’s D because the other ones don’t aren’t true
Answer:
The solution has a pH value of 9.3.
Explanation:
To solve this problem, we can first determine the H+ ion concentration and then use this value to calculate the pH. To find the H+ ion concentration from the OH- ion concentration, we should use Kw, which we know has a value of 1 * 10^(-14).
We can then use the following formula to solve for [H+]:
Kw = [H+][OH-]
10^(-14) = (2.02 * 10^(-5)) * [H+]
[H+] = 4.950495 * 10^(-10)
Now, we can find the pH using the formula pH = -log[H+].
pH = - log[H+]
pH = - log(4.950495 * 10^(-10))
pH = 9.3
Therefore, the correct answer is that the pH of the solution is 9.3. Note that an alternative way to solve the problem is to find the pOH from the OH- ion concentration and use the resulting value to determine the pH that way instead.
Hope this helps!
