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3 years ago

How does doubling the volume of solvent affect the concentration of the solution?

Chemistry

1 answer:

Alex17521 [72]3 years ago

8 0

Answer:

Molarity is halved when the volume of solvent is doubled.

Explanation:

Using the dilution equation (volume 1)(molarity 1)=(volume 2)(molarity 2), we can demonstrate the effects of doubling volume.

Suppose the starting volume is 1 L and the starting molarity is 1 M, and doubling the volume would make the final volume 2 L.

Plugging these numbers into the equation, we can figure out the final molarity.

(1 L)(1 M)=(2 L)(X M)

X M= (1 L x 1 M)/(2 L)

X M= 1/2 M

This shows that the molarity is halved when the volume of solvent is doubled.

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BaLLatris [955]

0.781 moles

Explanation:

We begin by balancing the chemical equation;

O₂ (g) + 2H₂ (g) → 2H₂O (g)

21.8 Liters = 21.8 Kgs

To find how many moles are in 28.1 Kg H₂O;

Molar mass of H₂O = 18 g/mol

28.1/18

= 1.56 moles

The mole ratio between water vapor and oxygen is;

1 : 2

x : 1.56

2x = 1.56

x = 1.56 / 2

x = 0.781

0.781 moles

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Hellllppppp lons Worksheet

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The metals will lose electrons while the non metals will gain electrons in order to attain octet structure.

An ion can be cation (positively charged) or anion (negatively charged).

Cations attain octet structure (8) by losing electron(s) while anions become stable or attains octet structure (8) by gaining electron(s).

The remaining elements are completed as follows to attain octet structure;

Element--valence electron--electrons to gain--electrons to lose--ion formed

O ------------ 6 ---------------------- 2 ------------------------ none -------------- $O^{2-}$

Ca -------- 2 ----------------------- none ---------------------- 2 ------------------ $Ca^{2+}$

Br ----------- 7 --------------------- 1 ------------------------ none --------------- $Br^{-}$

S ------------ 6 ----------------------- 2 ------------------------ none --------------- $S^{2-}$

Cl ------------ 7 ----------------------- 1 ------------------------ none ---------------- $Cl^{-}$

K -------------- 1 ----------------------- none ----------------------- 1 ------------------ $K^{+}$

Mg ------------ 2 ---------------------- none ---------------------- 2 ---------------- $Mg^{2+}$

Be ------------- 2 ---------------------- none ---------------------- 2 ---------------- $Be^{2+}$

Learn more here: brainly.com/question/21089350

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In the reaction N2 + 3H2 → 2NH3, what is the mole ratio of hydrogen to nitrogen?

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Answer: The mole ratio of hydrogen to nitrogen is 3 mole: 1 mole, 3:1

Explanation:

•Mole ratios are determined using the coefficients of the substances in the balanced chemical equation. •Each coefficient represents the number of mole of each substance in the chemical reaction.

•The mole ratio can be determined by first writing out a balanced chemical equation for the reaction.

For this reaction the balanced chemical equation is

N2(g) + 3H2(g) ----> 2NH3(g)

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From the equation we can see that 1 mole of N2(g) reacts with 3 moles of H2(g) or 3 moles of H2(g) react with 1 mole of N2(g) to produce 2 moles of NH3(g).

Therefore, the mole ratio of hydrogen to nitrogen is 3 mole: 1 mole, 3:1

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