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xenn [34]
2 years ago
13

HELP!!!! I WILL MARK BRAINLIEST WHOEVER ANSWERS FIRST

Chemistry
1 answer:
ELEN [110]2 years ago
8 0

Answer:

I answered first, give me brainliest

Explanation:

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What are the periodic trends of ionic radii? Check all that apply.
Troyanec [42]
Atomic radii increase when going down a group and decreases when going towards the anion periods. So A and D.
6 0
3 years ago
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If the moon resembled an asteroid, which theory would be most supported?
Law Incorporation [45]
<span>This is called "The capture theory" which states that the Earth's Moon was captured by the gravitational pull of our planet, meaning that it formed elsewhere, and then was pulle dinto place by the Earth, already formed. This would rely upon the ideas that a asteroid pased close enough to the Earth's orbit to be "captured".</span>
6 0
3 years ago
In the decomposition reaction, 1 mole of water (mw = 18.015 g/mol) was produced for every mole of cuo (mw = 79.545 g/mol) produc
natita [175]

Reactives -> Products

CuO and water are products.

I found this reaction which has CuO and water as products: decomposition of Cu(OH)2.

Cu(OH)2 -> CuO + H2O

Stoichiometry calculus involve the mole proportions you can see in the reaction: When 1 mole of Cu(OH)2 reacts, 1 mole of CuO and 1 mole of H2O are formed.

Considering the molar masses:

Cu(OH)2 = 83.56 g/mol

CuO = 79.545 g/mol

H2O = 18.015 g/mol

Then: When 83.56 g of Cu(OH)2 react, 79.545 g of CuO and 18.015 g H2O are formed.

You should use that numbers in the rule of three:

79.545 g CuO __________18.015 g water

3.327 g CuO__________ x =3.327*18.015 /79.545 g water 

x= 0.7535 g water




3 0
3 years ago
What mass of Sodium Chloride is required to make 100.0 mL of 3.0 M solution?
Julli [10]

Answer:

17.55 g of NaCl

Explanation:

The following data were obtained from the question:

Molarity = 3 M

Volume = 100.0 mL

Mass of NaCl =..?

Next, we shall convert 100.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

100 mL = 100/1000

100 mL = 0.1 L

Therefore, 100 mL is equivalent to 0.1 L.

Next, we shall determine the number of mole NaCl in the solution. This can be obtained as follow:

Molarity = 3 M

Volume = 0.1 L

Mole of NaCl =?

Molarity = mole /Volume

3 = mole of NaCl /0.1

Cross multiply

Mole of NaCl = 3 × 0.1

Mole of NaCl = 0.3 mole

Finally, we determine the mass of NaCl required to prepare the solution as follow:

Mole of NaCl = 0.3 mole

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =?

Mole = mass /Molar mass

0.3 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 0.3 × 58.5

Mass of NaCl = 17.55 g

Therefore, 17.55 g of NaCl is needed to prepare the solution.

5 0
3 years ago
Which of the following formulas represents an ionic compound?
Marta_Voda [28]

Answer:

BaI2

Explanation:

Hello, since the electronegativity of Barium and Iodine are 0.89 and 2.66, respectively, the difference is 1.77, so the bond is ionic.

Best regards.

5 0
3 years ago
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