Let A represent the speed of car A. Using your formula,
.. A*2 = D
.. (A +15)*1.5 = D . . . . . the same distance in a shorter time at a higher speed
Equating the two expressions for D, we get
.. 2A = 1.5(A +15)
.. 2A = 1.5A +22.5 . . . . . eliminate parentheses
.. 0.5A = 22.5 . . . . . . . . .subtract 1.5A
.. A = 22.5/0.5 = 45 . . . .divide by 0.5
Car B was 15 mph faster than this.
Car B traveled at 60 miles per hour.
I think it is 6 i hope i help please dont report bec i am sorry if ii get it wrong
A 45-45 90 triangle has two lengths that are equal, and the hypotenuse is √2 times those lengths.
Therefore:
Let x = the length of a leg (doesn't matter which one, they are equal)
√2 * x = 24 Divide both sides by √2
x = 24 / √2
To get the radical out of the denominator, multiply the right side by √2/√2
x = 24√2 / 2
x = 12√2 Answer is B
Answer:
Step-by-step explanation:
J is correct.. that function can never be less than 2