Math help please!!!! i will mark brainliest
1 answer:
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Answer:
The standard deviation of the load distribution is of 5102.041 pounds.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
Also, the probability that the load is between 10,000 and 30,000 pounds is 0.95.
10,000 pounds and 30,000 pounds are equidistant from the mean. Due to this, and the probability of 0.95 of having a value in this range, 10000 is the (100-95)/2 = 2.5th percentile and 30000 is the (100+95)/2 = 97.5th percentile. Applying one of them, we find the standard deviation.
30,000 is the 97.5th percentile:
This means that when X = 30000, Z has a pvalue of 0.975. So when X = 30000, Z = 1.96. Then
The standard deviation of the load distribution is of 5102.041 pounds.
Answer:
P( top two horses are predicted incorrectly in incorrect order)
=
Step-by-step explanation:
In the horse race the outcome can be predicted in 5! = 120 ways.
Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the top horse can be predicted incorrectly in 4 ways.
Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5
so the second horse can be predicted to be in place from 1 to (k - 1)
So, the top two horses can be predicted incorrectly in incorrect order
in = 10 ways
and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.
Hence ,
P( top two horses are predicted incorrectly in incorrect order)
=
=