A spinner is divided into many sections of equal size. Some sections are red, some are blue, and the remaining are green. The pr
2 answers:
Answer: Probability of the arrow landing on a green colored section is
Step-by-step explanation:
Since we have given that
Probability of the arrow landing on a section colored blue =
Probability of the arrow landing on a section colored red =
Since there are only three sections i.e. red, blue and green.
We need to find the probability of the arrow landing on a section colored green.
Required probability is given by
Hence, Probability of the arrow landing on a green colored section is
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Answer:
C: 12.5
Step-by-step explanation:
The sides x and 11 could be defined as the Adjacent angle and the Hypotenuse. This means that we will use the cos function to solve this.
First we can set up our equation
Next we can solve for x by multiplying by x and dividing by
Answer:
Ready Maid Cleaning Service's liabilities were $2930.
Step-by-step explanation:
At the end of a recent year, Ready Maid Cleaning Service, a full-service house and office cleaning service, had total assets of $ 5,810 and equity of $ 2,880.
Liabilities = assets - equity
So, Liabilities = dollars
Hence, Ready Maid Cleaning Service's liabilities were $2930.
Answer:
(1) 0.5933
(2) 0.8955
Step-by-step explanation:
We are given that all bags entering a research facility are screened.
Let Probability that bags entering the building contains forbidden material,
P(F) = 0.69
Probability that bags entering the building does not contains forbidden material, P(NF) = 1 - 0.69 = 0.31
Let event A = alarm gets triggered
Probability that alarm gets trigger given the bags contain forbidden material, P(A/F) = 0.77
Probability that alarm gets trigger given the bags does not contain forbidden material, P(A/NF) = 0.20
(1) Probability that a bag triggers the alarm, P(A) ;
P(A) = P(F) * P(A/F) + P(NF) * P(A/NF)
= (0.69 * 0.77) + (0.31 * 0.20) = 0.5313 + 0.062
= 0.5933
Therefore, probability that a bag triggers the alarm is 0.5933 .
(2) Probability that a bag that triggers the alarm will actually contain forbidden material is given by P(F/A) ;
Using Bayes' Theorem;
P(F/A) = =
=
= 0.8955