Answer:
Eq: (x+a/2)²+(y+1)²=(a²-8)/4
Center: O(-a/2, -1)
Radius: r=0.5×sqrt(a²-8)
Mandatory: a>2×sqrt(2)
Step-by-step explanation:
The circle with center in O(xo,yo) and radius r has the equation:
(x-xo)²+(y-yo)²=r²
We have:
x²+y²+ax+2y+3=0
But: x²+ax=x²+2(a/2)x+a²/4-a²/4= (x+a/2)²-a²/4
And
y²+2y+3=y²+2y+1+2=(y+1)²+2
Replacing, we get:
(x+a/2)²-a²/4+(y+1)²+2=0
(x+a/2)²+(y+1)²=a²/4-2=(a²-8)/4
By visual inspection we note that:
- center of circle: O(-a/2, -1)
- radius: r=sqrt((a²-8)/4)=0.5×sqrt(a²-8). This means a²>8 or a>2×sqrt(2)
I have no idea how to do this problem i dont know what a is
So what does it want you to what’s the equation
Answer:
x y
15 -1
12 0
9 1
6 2
3 3
0 4
Step-by-step explanation:
This is a function table. For a linear function, find the average rate of change between the listed points called slope. Then use the slope to fill in other inputs and outputs for the function.
This means for every 3 units made in the input, the function moves down 1 output.
x y
15 -1
12 0
9 1
6 2
3 3
0 4
How much was each candle worth?? if he sold and equal amount of both, he would have sold 72 of both candles.
