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DaniilM [7]
3 years ago
6

Find the distance between the points (3,8) and (11,10)

Mathematics
1 answer:
ikadub [295]3 years ago
3 0
8.24621 is the distance between the points
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Solve the system by elimination<br> x + y = 2 , –3x + 4y = 15
Nitella [24]

Answer:

x=−y+2,   x= 4/3 Y -5

Step-by-step explanation:

(/=fraction btw and the Y goes in the middle of the line for the fraction!)

7 0
3 years ago
-2x + 10 +4x=70 (what is X?)
Dovator [93]

Answer:

x = 30

Step-by-step explanation:

-2x + 10 +4x=70

      -10          -10

-2x + 4x = 60

2x = 60

/2      /2

x = 30

8 0
4 years ago
Read 2 more answers
(04.02 MC)
Elena L [17]

Answer:

0.1384

Step-by-step explanation:

Using binomial probability:

P = nCr p^r q^(n-r)

where n is the number of trials,

r is the number of successes,

p is the probability of success,

and q is the probability of failure (1-p).

Given n = 25, r = 4, p = 0.10, and q = 0.90:

P = ₂₅C₄ (0.10)⁴ (0.90)²⁵⁻⁴

P = 12650 (0.10)⁴ (0.90)²¹

P = 0.1384

6 0
3 years ago
The rabbit population in certain area is 200% of last year’s population. There are 1,100 rabbits this year. How many were there
IRINA_888 [86]

Answer:

550

Step-by-step explanation:

If it is 200% more you have to divide by two and you get 550

5 0
3 years ago
Plz help :)))))))))))
dusya [7]

Given:

b1 = 17 ft

b2 = 20 ft

h = 13 ft

r = 17/2 = 8.5 ft


Area of the Semi-circle = 1/2 π r²

= 1/2 (22/7) (8.5²)

= (11/7) (72.25)

= 113.535 ft²


Area of the trapezium = (h) (b1 + b2) / 2

= (13)(17 + 20)/2

= 240.5 ft²


Total area of the amphitheater stage = Area of Semi-circle + Area of the trazezium = 113.535 + 240.5 = 354.035 ft²

5 0
3 years ago
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