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babymother [125]
3 years ago
5

PLS HELP I NEED THIS DONE IN 3 HOURS PLSSSS

Mathematics
2 answers:
miskamm [114]3 years ago
3 0

Answer:

You ain't got nothing my man

Step-by-step explanation:

8090 [49]3 years ago
3 0
What do u need help with?
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A soccer ball was kicked in the air and follows the path h(x)=−2x2+1x+6, where x is the time in seconds and h is the height of t
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The ball will hit the ground at 2 seconds.

Step-by-step explanation:

Given that,

The path of the ball = h(x)=−2x2+1x+6

Here,

x is the time while h is the height of ball.

When the ball will hit the ground, the height will become zero. Therefore,

h(x)=−2x2+1x+6

0 =−2x2+1x+6

or

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x = \frac{-b +- \sqrt{b^{2} - 4ac }   }{2a}

here,

a = 2

b = -1

c = -6

Putting these values in formula, we get

x = \frac{-(-1) +- \sqrt{-1^{2} - 4.2.-6 }   }{2.2}

x = \frac{1 +- \sqrt{1 + 48 }   }{4}

x = \frac{1 +- \sqrt{49 }   }{4}

x = \frac{1 +- 7   }{4}

x = 2, -3/2

As the time cannot be negative. Therefore, the ball will hit the ground at 2 seconds.

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I hope this helps you




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