Question

In ΔABC shown below, BD over BA equals BE over BC: Triangle ABC with segment DE intersecting sides AB and BC respectively. The following flowchart proof with missing statements and reasons proves that if a line intersects two sides of a triangle and divides these sides proportionally, the line is parallel to the third side: Top path, by Given the ratio of line segments BD to BA is equal to the ratio of line segments BE to BC. By Side Angle Side Similarity Postulate, triangle ABC is similar to triangle DBE. By Corresponding Parts of Similar Triangles, angle BDE is congruent to angle BAC. By Converse of the Corresponding Angles Postulate, line segment DE is parallel to line segment AC. Bottom path, by space labeled as 2, space labeled by 1 occurs. By Side Angle Side Similarity Postulate, triangle ABC is similar to triangle DBE. By Corresponding Parts of Similar Triangles, angle BDE is congruent to angle BAC. By Converse of the Corresponding Angles Postulate, line segment DE is parallel to line segment AC. Which reason can be used to fill in the numbered blank space? 1. ∠A ≅ ∠A 2. Reflexive Property of Equality 1. ∠A ≅ ∠B 2. Corresponding Parts of Similar Triangles 1. ∠A ≅ ∠B 2. Corresponding Angles Postulate 1. ∠B ≅ ∠B 2. Reflexive Property of Equality

Answer 1

Answer:

  1. ∠B ≅ ∠B

  2. Reflexive Property of Equality

Step-by-step explanation:

Corresponding sides are shown proportional in the top path.

In order to invoke SAS, corresponding angles must be shown congruent in the bottom path. Angle B is the the angle of interest in each of the relevant triangles, so it must be shown congruent to itself. The appropriate choice is ...

1. ∠B ≅ ∠B
2. Reflexive Property of Equality