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qwelly [4]
2 years ago
12

How do I simplify (6^-2)(3^-3)(3 x 6)^4? Not the answer, just the simplified expression.

Mathematics
1 answer:
Mazyrski [523]2 years ago
5 0

The simplification form of the provided expression is 108 after applying the integer exponent properties.

<h3>What is integer exponent?</h3>

In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.

We have an expression:

=\left(6^{-2}\right)\left(3^{-3}\right)\left(3\:\cdot \:6\right)^4

=\dfrac{1}{36}\cdot \dfrac{1}{27}\left(3\cdot \:6\right)^4

=\dfrac{1}{36}\cdot \dfrac{1}{27}\cdot \:81\cdot \:1296

=\dfrac{1}{36}\cdot \dfrac{1}{27}\cdot \dfrac{104976}{1}

=\dfrac{104976}{972}

= 108

Thus, the simplification form of the provided expression is 108 after applying the integer exponent properties.

Learn more about the integer exponent here:

brainly.com/question/4533599

#SPJ1

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<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

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tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

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