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lara31 [8.8K]
2 years ago
15

35 POINTS PLEASE HELP

Mathematics
2 answers:
pantera1 [17]2 years ago
5 0

Answer:

The percentage error of measurement is 5.63%

Step-by-step explanation:

Lunna [17]2 years ago
4 0

Answer:

The percentage error of measurement is 5.63 %

Step-by-step explanation:

Given as  :

The measure length of the fence = 150 feet

The actual length of the fence = 142 feet

Let the percentage error in measurement = x

So, x = \dfrac{\textrm measured value - \textrm actual value}{\textrm actual value} ×100

Or, x =  \dfrac{\textrm 150 - 142}{142} ×100

or, x = \dfrac{\textrm 8}{142} ×100

or, x = 5.63 %

Hence The percentage error of measurement is 5.63 %  Answer

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4. Find the standard from of the equation of a hyperbola whose foci are (-1,2), (5,2) and its vertices are end points of the dia
Ad libitum [116K]

The <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

<h3>How to find the standard equation of a hyperbola</h3>

In this problem we must determine the equation of the hyperbola in its <em>standard</em> form from the coordinates of the foci and a <em>general</em> equation of a circle. Based on the location of the foci, we see that the axis of symmetry of the hyperbola is parallel to the x-axis. Besides, the center of the hyperbola is the midpoint of the line segment with the foci as endpoints:

(h, k) = 0.5 · (- 1, 2) + 0.5 · (5, 2)

(h, k) = (2, 2)

To determine whether it is possible that the vertices are endpoints of the diameter of the circle, we proceed to modify the <em>general</em> equation of the circle into its <em>standard</em> form.

If the vertices of the hyperbola are endpoints of the diameter of the circle, then the center of the circle must be the midpoint of the line segment. By algebra we find that:

x² + y² - 4 · x - 4 · y + 4= 0​

(x² - 4 · x + 4) + (y² - 4 · y + 4) = 4

(x - 2)² + (y - 2)² = 2²

The center of the circle is the midpoint of the line segment. Now we proceed to determine the vertices of the hyperbola:

V₁(x, y) = (0, 2), V₂(x, y) = (4, 2)

And the distance from the center to any of the vertices is 2 (<em>semi-major</em> distance, a) and the semi-minor distance is:

b = √(c² - a²)

b = √(3² - 2²)

b = √5

Therefore, the <em>standard</em> form of the equation of the hyperbola that satisfies all conditions is (x - 2)²/4 - (y - 2)²/5 = 1 .

To learn more on hyperbolae: brainly.com/question/27799190

#SPJ1

5 0
1 year ago
(2p + 4) + 5 (p-1) - (p+7)
jonny [76]

<em>Your answer will be, </em><em>"6p - 8"</em>

Thanks,

<em>Deku ❤</em>

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*** I would double check my answers to make sure I didn’t make a mistake
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